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answer only the 15?? question given below    
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Asked by sarveshvibrantacademy | 26 Mar, 2019, 11:32: AM
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From q. 14 it is clear that the answer to the question is option (C) i.e. - (2mm) sin (5t - 40x)
 
Thus, we can see that Ar = 2mm
 
Now, we know, string power α A2,
 
Thus,
 
P subscript i over P subscript r equals 6 squared over 2 squared equals 36 over 4 equals 9 space T h u s comma P o w e r space r e f l e c t e d space i s comma space P subscript r space equals P subscript i over 9
 
Now, we know,
 
Pt = Pi - Pr 
 
Thus, the power transmitted, 
 
P subscript t space equals space P subscript i space minus fraction numerator space P subscript i over denominator 9 end fraction equals 8 over 9 P subscript i space end subscript
 
Thus, the percentage of power transmitted by a heavier string through the joint is,
8 over 9 cross times 100 equals 88.88 percent sign space almost equal to 89 percent sign
Answered by Shiwani Sawant | 26 Mar, 2019, 14:52: PM
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