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CBSE Class 12-science Answered

ans this plz
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Asked by ac9968252687 | 11 Jun, 2020, 19:46: PM
answered-by-expert Expert Answer
two cells having emf 4V and 2V and internal resistance 1ohm and 1 ohm are connected. We have to calculate the current through 6 ohm.
 
The combined resistance of 3 ohm and 6 ohm is
 
R subscript e f f end subscript equals fraction numerator 3 cross times 6 over denominator 3 plus 6 end fraction
R subscript e f f end subscript equals 2 o h m
T o t a l space r e s i s tan c e space o f space t h e space c i r c u i t
2 plus 2 plus 1 plus 1 equals 6 o h m
V subscript t o t a l end subscript equals 4 plus 2 equals 6 V
i equals 6 over 6 equals 1 A
N o w space 3 o h m space a n d space 6 space o h m space a r e space c o n n e c t e d space i n space p a r a l l e l
t h e r e f o r e space c u r r e n t space t h r o u g h space 6 space o h m space i s space g i v e n space b y space
i subscript 6 equals fraction numerator 3 cross times 1 over denominator 3 plus 6 end fraction equals 1 third A
Answered by Utkarsh Lokhande | 13 Jun, 2020, 06:09: AM
CBSE 12-science - Physics
Asked by jothisugashini216 | 16 Jul, 2024, 20:30: PM
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CBSE 12-science - Physics
Asked by prithviraj.chopra2011 | 14 Jul, 2024, 23:00: PM
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CBSE 12-science - Physics
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CBSE 12-science - Physics
Asked by axonuploadserver4 | 14 Jun, 2024, 17:41: PM
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CBSE 12-science - Physics
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Asked by goswamideepak16492 | 12 Jun, 2024, 10:18: AM
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CBSE 12-science - Physics
Asked by trishaktiprasadmallik693 | 11 Jun, 2024, 07:17: AM
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CBSE 12-science - Physics
Asked by rahuldevgayen4 | 10 Jun, 2024, 14:58: PM
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