an object floats in water such that 1/5 of its volume is above the surface of water. When the same object is made to float in sample of impure alchohol, the volume that remains outside the liquid is 1/20 of total volume. What will the relative density of the sample of alcohol?
Asked by kaustav1996 | 22nd Oct, 2010, 07:04: PM
Let σ be the density of water and ρ be the density of alcohol.
Let V be the fractional volume above the surface of water and V' be the fractional volume above the sample of impure alcohol
since objects floats on water, therefore the weight of alcohol displaced is equal to the weight of water displaced, then :
V' / V = σ / ρ
Now, plugging in the values and calculating, you may find the value of density of impure alcohol, folowing which relative density can also be found.
We hope this clarifies your doubt.
Answered by | 25th Oct, 2010, 12:58: PM
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