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An isosceles ΔABC is inscribed in the circle x2 + y2 = 16. From points A, B and C three ordinates are drawn
which cut the ellipse x2/16+y2/9=1
at the points P, Q and R respectively such that A and P are on the
opposite sides, Q and B are on the same side and C and R are on the same side of the major axis. If ΔPQR
is right angled at P and θ is the smallest angle of the ΔABC, then find the value of 16tan2θ + 8 tan θ + 9.
Asked by savithakruthik9945 | 15 Jul, 2022, 09:34: PM
Expert Answer
Answered by Renu Varma | 21 Jul, 2022, 11:22: AM
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