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An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electron is Ee and pe and that of photon is Eph and pph respectively, then the correct statement is Ee/Eph=2c/v Ee/Eph=v/2c Pe/Pph=2c/v Pe/Pph=v/2v

Asked by Vedantshinde4may | 01 Mar, 2019, 02:44: AM

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Answered by Ankit K | 01 Mar, 2019, 12:41: PM

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The maximum and minimum interference pattern by two cohorent sources is 9I and I. Find intensities of individual waves.

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Asked by sahupramod650 | 13 Nov, 2019, 09:41: AM

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JEE main - Physics

An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electron is Ee and pe and that of photon is Eph and pph respectively, then the correct statement is Ee/Eph=2c/v Ee/Eph=v/2c Pe/Pph=2c/v Pe/Pph=v/2v

Asked by Vedantshinde4may | 01 Mar, 2019, 02:44: AM

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