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An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electron is Ee and pe and that of photon is Eph and pph respectively, then the correct statement is Ee/Eph=2c/v Ee/Eph=v/2c Pe/Pph=2c/v Pe/Pph=v/2v

Asked by Vedantshinde4may | 01 Mar, 2019, 02:44: AM

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Answered by Ankit K | 01 Mar, 2019, 12:41: PM

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JEE main - Physics

Statement 1: Photons of the same frequency have the same energy and momentum. Statement 2: When energy is incident on a metal, a part of absorbed energy is used to free the electron from the metal surface and the remaining is converted to thermal energy. A. Both statements are true. B. Only statement 2 is true. C. Only statement 1 is true. D. Both statements are false.

Asked by kushalv238 | 02 Aug, 2021, 06:13: PM

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The maximum and minimum interference pattern by two cohorent sources is 9I and I. Find intensities of individual waves.

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Asked by sahupramod650 | 13 Nov, 2019, 09:41: AM

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JEE main - Physics

An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electron is Ee and pe and that of photon is Eph and pph respectively, then the correct statement is Ee/Eph=2c/v Ee/Eph=v/2c Pe/Pph=2c/v Pe/Pph=v/2v

Asked by Vedantshinde4may | 01 Mar, 2019, 02:44: AM

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