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ABCD is a parallelogram and E is the mid point of side BC. If DE and AB when produced meet at F, prove that AF = 2AB.

Asked by Topperlearning User | 16 Aug, 2017, 03:09: PM

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Answered by | 16 Aug, 2017, 05:09: PM

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ABCD is a parallelogram and E is the mid point of side BC. If DE and AB when produced meet at F, prove that AF = 2AB.

Asked by Topperlearning User | 16 Aug, 2017, 03:09: PM

ANSWERED BY EXPERT

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ABCD is a parallelogram. E and F are the mid points of the sides AB and CD respectively. Prove that the segments CE and AF trisect the diagonal BD.

Asked by Topperlearning User | 16 Aug, 2017, 03:10: PM

ANSWERED BY EXPERT

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