A triangle ABC is right angled at A. AL is perpendicular to BC.Prove that
Asked by masara
| 5th Dec, 2009,
04:38: PM
Expert Answer:
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In 
BLA and BAC
BAC = BLA (Both 90o)
LBA is common.
BLA 
BAC (By AA corollary)
So, ACB = BAL (By cpct)
Hence Proved.
Answered by
| 8th Dec, 2009,
04:23: PM
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