A triangle ABC is right angled at A. AL is perpendicular to BC.Prove that

Asked by masara | 5th Dec, 2009, 04:38: PM

Expert Answer:

In BLA and BAC

BAC = BLA            (Both 90o)

LBA is common.

BLA BAC   (By AA corollary)

So, ACB = BAL     (By cpct)

Hence Proved.  


Answered by  | 8th Dec, 2009, 04:23: PM

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