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CBSE Class 12-science Answered

a student walk at a speed of 2.5 km/he and reaches his school 6 minutes late. next day he increases his speed by 1 km/he and reaches the school 6 minutes early. how fur his school from his house?
Asked by sankarsarkarjtr066 | 04 Nov, 2023, 08:59: PM
answered-by-expert Expert Answer
Let d be the distance to be travelled to reach school .
 
If speed is 2.5 km/hr , time taken to travel = distance / speed =  ( d/2.5 ) hour
 
If above time is 6 minutes late , i.e. ( 6/60 ) hour = ( 1/10 ) hour late ,
 
then correct time  t to be taken to reach the school just in time is  
 
t = [ (d/2.5) - ( 1/10 ) ] hour  ...............................(1)
 
If speed is 3.5 km/hr , time taken to travel = ( d/3.5 ) hour
 
If above time is 6 minutes early , i.e., (1/10) hour early ,
 
then correct time to be taken to reach the school just in time is 
 
t = [ (d/3.5) + (1/10) ] hour  ..................................(2)
 
By equating equations (1) and (2) , we get
 
begin mathsize 14px style fraction numerator d over denominator 2.5 end fraction space minus space 1 over 10 space equals space fraction numerator d over denominator 3.5 end fraction plus 1 over 10 end style
 
By solving above equation, we get d = 1.75 km
 
Answered by Thiyagarajan K | 04 Nov, 2023, 10:02: PM
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