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a student walk at a speed of 2.5 km/he and reaches his school 6 minutes late. next day he increases his speed by 1 km/he and reaches the school 6 minutes early. how fur his school from his house?
Asked by sankarsarkarjtr066 | 04 Nov, 2023, 08:59: PM
Let d be the distance to be travelled to reach school .

If speed is 2.5 km/hr , time taken to travel = distance / speed =  ( d/2.5 ) hour

If above time is 6 minutes late , i.e. ( 6/60 ) hour = ( 1/10 ) hour late ,

then correct time  t to be taken to reach the school just in time is

t = [ (d/2.5) - ( 1/10 ) ] hour  ...............................(1)

If speed is 3.5 km/hr , time taken to travel = ( d/3.5 ) hour

If above time is 6 minutes early , i.e., (1/10) hour early ,

then correct time to be taken to reach the school just in time is

t = [ (d/3.5) + (1/10) ] hour  ..................................(2)

By equating equations (1) and (2) , we get

By solving above equation, we get d = 1.75 km

Answered by Thiyagarajan K | 04 Nov, 2023, 10:02: PM

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