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A stone falls freely under gravity .it covers distance h1,h2,h3 in the first 5s ,the next 5s and the next 5s respectivpy . The relatn between h1,h2,h3 is
Asked by srivastavsanjana6 | 31 Jan, 2018, 12:18: AM
We use the equations of motion S = ut+(1/2)gt2 and v = u+at

first 5 seconds:- h1 = (1/2)g(25) = 12.5 g, v1 = 5g

h1 is the distance travelled in 5 seconds and v1 is velocity at the end of 5 seconds. initial velocity is zero

next 5 seconds:- h2 = 5g(5) + (1/2)g(25) = 37.5 g, v2 = 10g

h2 is the distance travelled in next 5 seconds and v2 is velocity at the end of 10 seconds

nextt 5 seconds:- h3 = 10g(5)+(1/2)g(25) = 62.5 g, v3 = 15g

h3 is the distance travelled in next 5 seconds and v3 is velocity at the end of 15 seconds

we can find the relation as h3 = h1+h2+12.5g;

Answered by Thiyagarajan K | 31 Jan, 2018, 11:36: AM

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