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A square loop of wire of side 4 cm is placed 20 cm away from a concave mirror of focal length 8 cm. What is the area enclosed by the image of the wire (assume that the center of the loop is on the axis of the mirror and the two sides are normal to the axis)?
Asked by modi72879 | 21 Feb, 2018, 09:54: PM
mirror equation that involves focal lenth f, object-to-mirror distance u and image-to-mirror distance v is given by
we get v = 40/3 cm.  magnitude of magnification
area of image = 4×4×(2/3)×(2/3) = 7.11 sq.cm
Answered by Thiyagarajan K | 22 Feb, 2018, 12:30: PM

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