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A particle is moving under constant force it's distance (x) depend on time according to following relations : t=√x +3, then calculate displacement of particle at that time when it's velocity will be zero?
Asked by shuklaramakant.2016 | 15 Jul, 2022, 07:46: PM
t = + 3
= ( t - 3 )
Hence position x at time t is given as

x = (t-3)2 ....................................(1)

velocity v = dx/dt = 2 (t-3)   ......................... (2)

we get velocity v = 0 at t =3 from eqn.(2)

Initial position x at t = 0 is obtained from eqn.(1)

at t = 0 , x(0) = 9

position x at t = 3 is obtained from eqn.(1)

at t = 3 , x(3) = 0

displacement S at t = 3  is given as

S = x(3) - x(0) = 0 - 9 = -9

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