A particle is moving in a straight line with initial velocity U and uniform accerleration A. if the sum of distances travelled in Tth & (T+1)th second is 100 cm. Then find its velocity after T second in cm/s
Asked by SIDDHARTH SHARMA
| 24th Nov, 2014,
11:08: AM
Expert Answer:
We know that the distance travelled in nth second of uniformly accelerated motion is:
where u is the initial velocity and a the uniform acceleration of the body.
In this case given that the sum of distances travelled in T th & (T+1) th second is 100 cm
i.e.
S T +S T+1 =100
If the particle is moving with initial velocity U and uniform accerleration A,
Distance travelled by the particle in Tth second can be written as:
According to the equation of motion, we know that v = u+at
where v is the final velocity, u is the initial velocity, a the acceleration and t the time.
So comparing the equation U+AT =50 with the the equation of motion v= u+at
we get that the final velocity of the particle at T second = 50 cm/s
Answered by Jyothi Nair
| 25th Nov, 2014,
09:27: AM
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