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# CBSE Class 9 Answered

<div>A particle is moving in a straight line with initial velocity U and uniform accerleration A. if the sum of distances travelled in Tth &amp; (T+1)th second is 100 cm. Then find its velocity after T second in cm/s&nbsp;</div>
Asked by SIDDHARTH SHARMA | 24 Nov, 2014, 11:08: AM Expert Answer
We know that the distance travelled in nth second of uniformly accelerated motion is: where u is the initial velocity and a the uniform acceleration of the body.
In this case given that the sum of distances travelled in T th & (T+1) th second is 100 cm
i.e.
T +S T+1 =100
If the particle is moving with initial velocity U and uniform accerleration A,
Distance travelled by the particle in Tth second can be written as: According to the equation of motion, we know that v = u+at
where v is the final velocity, u is the initial velocity, a the acceleration and t the time.
So comparing the equation U+AT =50 with the the equation of motion v= u+at
we get that the final velocity of the particle at T second  = 50 cm/s

Answered by Jyothi Nair | 25 Nov, 2014, 09:27: AM

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