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CBSE Class 12-science Answered

A parallel plate capacitor has capacitance C in air. What should be the thickness of dielectric (dielectric constant k = 4) to be inserted between the capacitor so that capacitance becomes 8/5 times of C if the space between plates is 4cm?
Asked by nikitaputhamakula169 | 10 May, 2020, 12:29: PM
answered-by-expert Expert Answer
C a p a c i tan c e space i s space C equals fraction numerator epsilon A over denominator d minus t plus begin display style t over k end style end fraction W h e n space a i r space i s space f i l l e d space b e t w e e n space t h e space c a p a c i t o r space p l a t e s C equals fraction numerator epsilon A over denominator 4 minus 0 plus begin display style 0 over 4 end style end fraction C equals fraction numerator epsilon A over denominator 4 end fraction N o w space a space d i e l e c t r i c space o f space K equals 4 space i s space i n s e r t e d space t h e n C to the power of apostrophe equals fraction numerator epsilon A over denominator 4 minus t plus begin display style t over 4 end style end fraction C to the power of apostrophe equals 8 over 5 C T h e r e f o r e 8 over 5 fraction numerator epsilon A over denominator 4 end fraction equals fraction numerator epsilon A over denominator 4 minus t plus begin display style t over 4 end style end fraction O n space s o l v i n g space w e space g e t space t equals 2 c m
Answered by Utkarsh Lokhande | 11 May, 2020, 10:24: AM

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