A monochromatic source , emitting light of wavelength , 600 nm , has a power output of 66 W. Calculate the number of photons emitted by this source in 2 minutes.
Asked by vinitapahel123
| 13th Dec, 2015,
12:04: PM
Expert Answer:
Given:
Wavelength, λ = 600nm = 6×10-7 m
Power, P = 66 W
Energy of one photon, E = 
Let n is the number of photons emitted per second such that the energy emitted in one second is 66 J.
nE = 66
Total number of photons emitted by source in 2 mins = n × 2 × 60 = 2.388 × 1022 photons. [2 mins = 2 × 60]
nE = 66
Answered by Faiza Lambe
| 13th Dec, 2015,
03:41: PM
Concept Videos
- what is the princple of working laser light?
- The threshold wavelength of a photosensitive metal is 275nm.calculate the maximum velocity of the photoelectron ejected when light of 180nm is incident on it. How to solve this??
- In the wave picture of light, intensity of light is determined by square of the amplitude of wave. What determines the intensity of light in the photon picture of light?
- How would you prove the dual nature of matter?
- What is the nature of matter waves?
- Why is the wave nature of particle not observable in daily life?
- Are matter waves electromagnetic in nature?
- Is a moving particle equivalent to a single wave?
- Is the de Broglie wavelength of a photon of an electromagnetic radiation equal to wavelength of a radiation?
- How do matter waves differ from a light wave as regards the velocity of the particle and the wave?
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change