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A horse and an ox are tied to a pet at opposite corners of a rectangular field of dimension 35 m x 20 m by ropes of length 5 m and 10 m respectively (use pi=3.14 ) The area of the field that the horse can graze is given by ------- sq.m The area of the field the ox can graze is a-------- sq.m. The area of the field left to be grazed is --------- sq.m. If the rope to which horse is tied would have been 8 m long, then the increase in the grazing area is given by _______ sq.m.
Asked by bhavikabhatia1125 | 18 Sep, 2021, 04:50: PM
Figure shows the field of size 35 m x 20 m .  Let the horse is tied at corber D with a rope of length 5 m .

Let the Ox be tied at corner B with rope of length 10m .

Total area of the field = 35 m × 20 m = 700 m

Area gazed by Horse = ( π / 4 ) 5 × 5 = 19.63 m2

Area gazed by Ox = ( π / 4 ) 10 × 10 = 78.54 m2

Area left to be gazed = ( 700 - 19.63 -78.54 ) = 601.83 m2

------------------------------------------------------------------------------

If the horse is tied to a rope of length 8 m , then area gazed by horse = ( π / 4 ) 8 × 8 =  50.26 m2

Increase in gazed area = ( 50.26 - 19.63 ) m2 = 30.63 m2
Answered by Thiyagarajan K | 19 Sep, 2021, 12:19: AM

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