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CBSE Class 9 Answered

A hammer of mass 500g, moving at 50m/s, strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer?

Asked by dhanrajshivalekar | 13 Nov, 2018, 02:00: PM
Expert Answer
We know,
F = m x a
 
a = (v-u)/t
F = m x (v-u)/t 
Thus, F = 0.5 x (50-0)/0.01
F = 2500 N 
Answered by Shiwani Sawant | 13 Nov, 2018, 03:35: PM
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