A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 ohm when connected to a 10v battery. calculate the resistance of electric lamp. now if a resistance of 10 ohm is connected in parallel with this series combination, what change in current flowing through 5 ohm conductor and potential difference across the lamp will take place? give reason
Asked by richaverma914 | 19th May, 2015, 07:27: PM
Therefore the resistance of the electric lamp = 5 Ω
When a resistance of 10 ohm is connected in parallel with this series combination, the circuit will be as shown below:
The current flowing through both the branches will be 1 V each
i.e. 1 V current flows through 10Ω resistance and 5Ω conductor.
There will be no chnage in the current flowing through 5 ohm conductor and potential difference across the lamp.
As voltage remains the same in both the branches the potential difference across the lamp will also remain the same.
Answered by Jyothi Nair | 20th May, 2015, 09:13: AM
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