Asked by Paresh | 1st Dec, 2015, 08:47: PM
ii. Let the height of the water column be 'h'.
In equilibrium condition: Weight of the iron block = Total upthrust
i.e, V dirong = Upthrust of water + Upthrust of mercury
1000 × 7.2 × g = h × 100 × 1 × g + (10 - h) × 100 × 13.6 g
72 = h + 136 - 13.6 h
72 = 136 - 12.6 h
12.6 h = 136 - 72
12.6 h = 64
y = 5.08 cm
Answered by Yashvanti Jain | 2nd Dec, 2015, 10:21: AM
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