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A body starts from rest from origin with acceleration 6m/s2 along X-axis and 8m/s2 along Y-axis. Its distance from origin aftr 4 seconds will be ?
Asked by simashreegogoi014 | 12 Jul, 2019, 23:59: PM
answered-by-expert Expert Answer
displacement S of a body after t seconds starting from rest and moving with acceleration a is given by, S = (1/2)at2
 
Hence displacement in x-direction after 4 s :- (1/2)×6×4×4 = 48 m
Hence displacement in y-direction after 4 s :- (1/2)×8×4×4 = 64 m
 
Distance from origin after 4 s = begin mathsize 12px style square root of 48 squared plus 64 squared end root space equals space 80 space m end style
Answered by Thiyagarajan K | 13 Jul, 2019, 10:17: AM

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