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a body of mass 2kg is allowed to fall freely from a height of 5m above the ground. what is the total energy of the body at the half of the journeyhal body at the half of the jo
Asked by lakshmikantbiswas.lkb | 20 Nov, 2020, 09:58: PM
When mass is at height 5 m
Its potential energy = mgh

g = 9.8 m/s2
Thus, P.E.  = 2 x 9.8 x 5 = 98 J
Wehn object is at maximum height P.E. = maximum and K.E. = 0
When ball is allowed to fall down and reaches the midpoint of the height
h = 2.5 m
Thus,
P.E = 2 x 9.8 x 2.5 = 49 J
We know,
Total energy = Potential energy + Kinetic energy .... (by law of conservation of energy)
In this case,
T.E. = 98 J
as at half of the journey in this case - K.E. = 49 J and P.E. = 49 J

Answered by Shiwani Sawant | 23 Nov, 2020, 02:01: PM

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