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a body moving with a uniform acceleration travels 4m in the 3rd second and 12m in the 5th second.The distance travelled by the body in the next three seconds
Asked by sssbscity | 08 Jan, 2024, 09:08: PM

The distance travelled by a body in 'n' seconds is,

Sn = u + (a/2) × (2n - 1)

S3 = u + (a/2) × (5)

We know, S3 = 4

4 = u + (5a/2) ... (1) (here n = 3)

S5 = u + (a/2) × (9) (here n = 5)

We know, S5 = 12

12 = u + (a/2) × (9) ... (2)

On solving equations (1) and (2),  we get

u = - 6 m/s

and a = 4 m/s2

Thus, distance covered in 8 s,

S1 = - 6 × 8 + 1/2 × 4 × 25 = 80 m

Distance covered in 5 s,

S2 = -6 × 5 + (1/2) × 4 × 25 = 20 m

Thus, the distance travelled in the next 3 seconds,

= 80 m - 20 m = 60 m

Answered by Shiwani Sawant | 09 Jan, 2024, 11:51: AM

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