CBSE Class 6 Answered
a body moving with a uniform acceleration travels 4m in the 3rd second and 12m in the 5th second.The distance travelled by the body in the next three seconds
Asked by sssbscity | 08 Jan, 2024, 21:08: PM
Expert Answer
The distance travelled by a body in 'n' seconds is,
Sn = u + (a/2) × (2n - 1)
S3 = u + (a/2) × (5)
We know, S3 = 4
4 = u + (5a/2) ... (1) (here n = 3)
S5 = u + (a/2) × (9) (here n = 5)
We know, S5 = 12
12 = u + (a/2) × (9) ... (2)
On solving equations (1) and (2), we get
u = - 6 m/s
and a = 4 m/s2
Thus, distance covered in 8 s,
S1 = - 6 × 8 + 1/2 × 4 × 25 = 80 m
Distance covered in 5 s,
S2 = -6 × 5 + (1/2) × 4 × 25 = 20 m
Thus, the distance travelled in the next 3 seconds,
= 80 m - 20 m = 60 m
Answered by Shiwani Sawant | 09 Jan, 2024, 11:51: AM
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