NEET Class neet Answered
A body is projected with velocity u such that it's horizontal range and maximum vertical height are same.the maximum height is
Asked by Singhalahan3 | 12 Aug, 2019, 08:13: PM
Expert Answer
Horizontal range, R = ( u2 sin2α )/ (2g) ......................(1)
where u is projection velocity and α is angle of projection
Maximum height , H = ( u2 sin2α ) / (2g) .....................(2)
if range and maximum height are same, then ( u2 sin2α )/ (2g) = ( u2 sin2α ) / (2g) ....................(3)
from eqn.(3), we get, tanα = 2 or sinα = 2/√5
Hence maximum height = (4/5) u2 / (2g)
Answered by Thiyagarajan K | 13 Aug, 2019, 06:40: AM
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