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CBSE Class 9 Answered

a ball is thrown vertically upwards withe an initial velocity u from the top of a tower, reaches the ground with velocity 3u. find the height of tower?
Asked by | 08 Jun, 2012, 02:09: PM
answered-by-expert Expert Answer
When the ball is thrown vertically upwards with velocity u , then distance it covers from the top of the tower is calculated by  
v2- u2 = 2aS1
0 - u2 = 2(-g)S1
S1 = u2/2g
 
Now, next Distance covered by the ball is S1+ height of the tower to reach the ground
 
Now , v2- u2 = 2a(S1+ h)
 
(3u)2 - 0 = 2g(u2/2g + h)
 
9u2/2g = (u2/2g + h)
 
9u2/2g - u2/2g = h
 
4u2/g = h
Answered by | 08 Jun, 2012, 06:02: PM

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