A ball is thrown vertically upwards with an initial velocity such that it can reach a maximum height of 15m. If at the same instance, a stone is dropped from a height of 15m. , find the ratio of distances traveled by them when they cross each other. Please explain clearly.

Asked by Shourya Mukherjee | 22nd May, 2012, 07:04: PM

Expert Answer:

(i) Time of Motion of A = Time of Motion of B = 1/2 Time of Desent of B
(ii) Let x be the distnace travelled by the ball
(iii) Let y be the distance travelled by the stone
(iv) time of Flight = sqrt (2h/g)  where h = x+y
(v) Time of desend of stone = qrt (2y/g)
(v) from equation III & IV , obtaine relation between x & y
(vi) find the ratio of x & y
value is 3:1

Answered by  | 31st May, 2012, 11:06: AM

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