CBSE Class 9 Answered
A ball is dropped on to the floor from a height of 10 cm. It rebounds to a height of 2.5m. If the ball is in contact with the floor for o.o1 seconds , what is the average accelerationduring contact ??
Asked by SIDDHARTH SHARMA | 24 Nov, 2014, 11:12: AM
Expert Answer
The height from which the ball is dropped cannot be 10 cm, it will be 10 m as the ball is said to rebound 2.5 m.
Given, the height from which the ball is dropped, h1 =10 m,
The height to which the ball rebounds, h2 = 2.5 m
Time of contact of the ball with floor, Δt = 0.01 sec
Let v1 be the velocity of the ball when dropped before striking the floor,
v2 be the velocity of ball upwards after striking the floor during rebounding
Change in velocity of ball during contact =v2 - (-v1)
Average acceleration = 2100 m/s2
Answered by Jyothi Nair | 24 Nov, 2014, 03:36: PM
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