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A bag contains 5 white balls, 7 red balls, 4 black balls and 2 blue balls. One ball is drawn at random from the bag. What is the probability that the ball drawn is (i) white or blue (ii) red or black (iii) not white (iv) neither white nor black?
Asked by Topperlearning User | 27 Jul, 2017, 04:28: PM

Total number of balls = 5 + 7 + 4 + 2 = 18

(i) Favourable outcomes = 5 + 2 = 7

\\Required probability =

(ii) Favourable outcomes = 7 + 4 = 11

\\ Required probability =

(iii) Number of balls which are not white = 18 - 5 = 13

\\Required probability =

(iv) Number of balls which are neither white nor black = Number of balls which are red or blue = 7 + 2 = 9

\\ Required probability ==

Answered by | 27 Jul, 2017, 06:28: PM

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