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a and b are integers such that 10a+b=5 and p(x)=x+ax+b
also p(10)p(11)=p(n) then find n
Asked by latajadhavshinde | 04 Apr, 2024, 11:05: PM
Expert Answer
p(x) = x + a x + b
p(10 ) = 10 + 10 a + b = 10 + 5 = 15 , because it is given that 10a + b = 5
p(11) = 11 + 11 a + b = 10 + 10a +b + a + 1 = 16 + a
p(10)p(11) = 15 ( 16 + a ) = 240 + 15 a ...........................(1)
if p(10) p(11) = p(n) = n + a n + b = n + a n + 5 - 10 a
p(10)p(11) = a ( n - 10) + ( n + 5 ) .........................(2)
if we compare (1) and (2)
we get from coefficient a , n -10 = 15 or n = 25
we get from constant term , n+5 = 240 or n = 235
value of n got from coefficient of a and value of n got from constant term are not consistent.
Hence the formulation of probelm is wrong .
Answered by Thiyagarajan K | 09 Apr, 2024, 03:58: PM
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