a^3-a-120

Asked by Sukhad Sahu | 12th May, 2013, 02:49: PM

Expert Answer:

f(a) = a^3-a-120 
Now by hit and trial, f(5) = 125 -5 - 120 = 0
Hence (a-5) is a root of f(a)
Then using long division method with a-5 as the divisor
f(x) = (a-5) (a^2+5a+24)

Answered by  | 12th May, 2013, 04:10: PM

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