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Asked by murtazan92 | 20 Nov, 2023, 11:45: PM
Expert Answer
Dear Student,
Answer for query no. 35
The order of basicity of given compounds is
(A) C6H5NH2 < (B) CH3NH2 < (D) (CH3)3N < (C) (CH3)2NH
Methyl amine is more basic than Aniline since lone pair of electrons on nitrogen in aniline is attracted towards stable aromatic nucleus so less available.
More the electron donating alkyl groups, more the basicity, so methylamine is less basic than di and tri methyl amines.
Dimethyl amine is more basic than trimethylamine because of steric crowding of methyl groups in trimethylamine.
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Answered by | 21 Nov, 2023, 09:49: AM
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