ICSE Class 10 Answered
11-2x/5 greater than equal 9-3x/8 + 3/4 how to solve this
Asked by KANRAR.SOUMEN | 15 Dec, 2022, 12:26: PM
(11-2x)/5 >= (9-3x)/8 + 3/4
![fraction numerator 11 minus 2 straight x over denominator 5 end fraction greater or equal than fraction numerator left parenthesis 9 minus 3 straight x right parenthesis over denominator 8 end fraction plus 6 over 8
fraction numerator 11 minus 2 straight x over denominator 5 end fraction greater or equal than fraction numerator 9 minus 3 straight x plus 6 over denominator 8 end fraction
8 left parenthesis 11 minus 2 straight x right parenthesis greater or equal than 5 left parenthesis 9 minus 3 straight x plus 6 right parenthesis
8 left parenthesis 11 minus 2 straight x right parenthesis greater or equal than 5 left parenthesis 15 minus 3 straight x right parenthesis
88 minus 16 straight x greater or equal than 75 minus 15 straight x
88 minus 75 greater or equal than 16 straight x minus 15 straight x
13 greater or equal than straight x
rightwards double arrow straight x less or equal than 13](https://images.topperlearning.com/topper/tinymce/cache/9c2cc35fec32c5e0aed9d104666dee3d.png)
Answered by Renu Varma | 15 Dec, 2022, 16:43: PM
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