NEET Class neet Answered
0.5 mole of a diatomic gas at 27°C is heated at constant pressure so that its volume is trebled. If R=8.3 J/mol-K then the work done is
Asked by gvr20689 | 18 Aug, 2019, 09:55: PM
Expert Answer
Let p be constant pressure, Vi is initial volume, Vf is final volume, n is number of moles and Ti is initial temperature 300 K
Workdone at constant pressure, W = p(Vf - Vi) = p(3Vi - Vi) = 2pVi = 2×n×R×Ti = 2×0.5×8.3×300 = 2.49 kJ
Answered by Thiyagarajan K | 18 Aug, 2019, 10:46: PM
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