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Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power - Turning Effect of Force and Equilibrium

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Frank Textbook Solutions Chapter Unit - 1 - Force, Work, Energy and Power - Turning Effect of Force and Equilibrium

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 10 Physics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter Unit - 1 - Force, Work, Energy and Power - Turning Effect of Force and Equilibrium for the Frank textbook.

Frank Textbook Solutions for class 10 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 10 Physics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 10 students can refer to our solutions while doing their homework and while preparing for the exam.

 

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Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power - Turning Effect of Force and Equilibrium Page/Excercise 21

Solution 1

The turning effect produced by a force on a rigid body about a point, pivot or fulcrum is called the moment of force or torque. It is measured by the product of force and the perpendicular distance of the pivot from the line of action of force.
Moment of a force = Force x perpendicular distance of the pivot from the force.
Its SI unit is newton-metre (Nm).

Solution 2

The moment of force is a vector quantity.

Solution 3

Torque

Solution 4

When some force is applied on a rigid body free to move and the body starts moving along a straight path in the direction of force. This is known as linear or translational motion. Points on the rigid body, undergo displacements forming parallel lines and magnitude of displacement is the same for individual point.
e.g. the motion of a bullet fired from a gun, a ball thrown straight up and falling back straight down.

Solution 5

If a rigid body is pivoted at a point, then the applied force will rotate the body about the fixed point or about the axis passing through the fixed point. This motion is called rotational motion.
e.g. Earth's rotation about its axis, wheels of car in motion.

Solution 6

1 Nm = 107 dyne cm

Solution 7

The factors on which the moment of force about a point depends are:
1. The magnitude of force applied.
2. The distance of the line of action of the force from the axis of rotation.

Solution 8

If the turning effect on the body is clockwise, moment of force is called the clockwise moment and is taken as negative.
If the turning effect on the body is anticlockwise, moment of force is called the anticlockwise moment and is taken as positive.

Solution 9

(i) If a rigid body is free to move, the applied force will cause translational motion.
(ii) If a rigid body moves around a center or is pivoted at a point, the applied force will cause rotational motion.

Solution 10

This is so because near the free end, the distance of the point of application of force from the axis of rotation becomes maximum, so the torque (= Force x perpendicular distance of the pivot from the force) is very large and hence it is easier to open the door.

Solution 11

A long handle facilitates increased torque with small application of force; hence a spanner has a long handle.

Solution 12

A body is said to be in equilibrium under the action of a number of forces, if the forces are not able to produce any change in the state of rest or of uniform motion or uniform rotation.
Equilibrium is a state of zero acceleration.

Solution 13

(i) The conditions for static equilibrium are:
(a) The sum of the (vector) forces must equal zero, i.e. ? F = 0
(b) The sum of the torques must equal zero; i.e. ? ? = 0.
(ii) The conditions for dynamic equilibrium are:
(a) The body should have a broad base.
(b) Centre of gravity of the body should be as low as possible.
(c) Vertical line drawn from the centre of gravity should fall within the base of the support.
Examples:
Static equilibrium: a box at rest on a floor; there is a gravitational force pulling the object to the earth, but there is also an equal and opposite force applied by the floor to the box (pushing up).
Dynamic equilibrium: A rock travelling across the cosmos, far enough away from any other object (so as not to be affected by gravity - in other words, in zero gravity conditions); the rock continues to travel in a straight line at uniform velocity either for eternity, or until acted upon by an external unbalanced force.

Solution 14

Conditions for equilibrium:
(a) Vector sum of forces acting on the body should be zero.
(b) Algebraic sum of moments acting on the body should be zero.

Solution 15

Principle of moments: If a body is in equilibrium under the action of number of force, then the sum of clockwise moments is equal to the sum of anticlockwise moments.

Solution 16

Solution 17

Examples of couple action in daily life:
(i) Opening and closing the cap of a bottle
(ii) Turning a key in a lock

Solution 18

(i) Force 'R' has the least moment about 'O' because its perpendicular distance is least from 'O'.
(ii) Force 'P' has the maximum moment about 'O' because its perpendicular distance is maximum from 'O'.

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power - Turning Effect of Force and Equilibrium Page/Excercise 22

Solution 19

Two equal and opposite parallel forces acting along different lines on a body constitute a couple.
Effect of couple: It produces angular acceleration.

Solution 20

The turning effect of a couple is called the moment of couple and is calculated by the product of either of the forces and the perpendicular distance between them.
Its SI unit is Nm.

Solution 21

Solution 22

Solution 23

Solution 24

Conditions of equilibrium for a rigid body:
1. The body should have a broad base.
2. Center of gravity of the body should be as low as possible.
3. Vertical line drawn from the center of gravity should fall within the base of
support.
4. Vector sum of forces acting on the body should be zero.
5.  Algebraic sum of moments acting on the body should be zero.

Frank Modern Certificate Physics - Part II Class 10 Chapter Solutions

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter Unit - 1 - Force, Work, Energy and Power - Turning Effect of Force and Equilibrium here. Our Frank Textbook Solutions for ICSE Class 10 Physics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

Text Book Solutions

ICSE X - Physics

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