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Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work

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Frank Textbook Solutions Chapter 12 - Practical Work

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 10 Chemistry exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter 12 - Practical Work for the Frank textbook.

Frank Textbook Solutions for class 10 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 10 Chemistry will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 10 students can refer to our solutions while doing their homework and while preparing for the exam.

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Exercise/Page

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 307

Solution 1

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

(a) i) Bluish green crystalline solid, on heating, melts to form a bluish green mass and gives off steamy vapours which condense on the cooler part of the test tube.

 ii) On further heating, the bluish green mass changes to a black residue.

 iii) It gives off a reddish brown gas and gives a gas which rekindles a glowing splinter, i.e. oxygen.

(b) i) A white solid turns yellow on heating.

 ii) Gives off a gas which extinguishes a burning wooden splinter.

 iii) Gas evolved turns lime water milky.

(c) i) When ammonium chloride is heated in a test tube, the lighter ammonia gas will emerge first and turn a piece of moist red litmus paper blue.

 ii) Hydrogen chloride coming up next will change the  

 litmus paper from blue back to red.

Solution 7

Solution 8

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 308

Solution 9

Solution 10

Solution 1999-1

Solution 2000-1

Solution 2001-1

Solution 2001-2

Solution 2002-1


Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 309

Solution 2003-1

Solution 2004-1

Solution 2004-2

Solution 2005-1

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 310

Solution 2006-1

Solution 2006-2

Solution 2007-1

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 311

Solution 2008-1

Solution 2010-1

(i) Iron (III) chloride

(ii) Lead (II) chloride

(iii)Nitroso iron (II) sulphate

(iv)Sodium chloride

(v) Chromium sulphate

Solution 2011-1

On addition of ammonium hydroxide in a small quantity, a blue-coloured copper hydroxide precipitate is formed. This copper hydroxide of light blue colour dissolves in excess of ammonium hydroxide to yield a deep blue solution.

Solution 2011-2

(i) D

(ii) C

(iii) E

(iv) A

(v) F

(vi) B 

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 312

Solution 2013-1

(i) Lead nitrate decrepitates on heating; a yellow solid is formed and it fuses with glass. Lead nitrate decomposes to lead oxide, nitrogen dioxide and oxygen. 

(ii) Oxygen is evolved.

  2KNO3 2KNO2 + O2

Solution 2013-2

(i) Add silver nitrate solution to both solutions. Sodium chloride will form a curdy white ppt., whereas sodium nitrate will not undergo any reaction.

(ii) Hydrogen chloride gas gives thick white fumes of ammonium chloride when a glass rod dipped in ammonia solution is held near the vapour of the acid, whereas no white fumes are observed in case of hydrogen sulphide gas.

(iii) Calcium nitrate forms no ppt. even with addition of excess of NH4OH, whereas zinc nitrate forms a white gelatinous ppt. which dissolves in excess of NH4OH.

(iv) Carbon dioxide gas has no effect on acidified KMnO4 or K2Cr2O7, but sulphur dioxide turns potassium permanganate from pink to colourless.

Solution 2013-3

 Sulphuric acid precipitates the insoluble sulphate of barium from the solution of barium chloride.

BaCl2 + H2SO4 BaSO4 + 2HCl

Dilute HCl does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.

Solution 2014-1

(i) On carrying out the flame test with a salt P, a brick red flame is obtained. Hence, the cation P is Ca2+.

(ii) A gas Q turns moist lead acetate paper silvery black. Hence, the gas is H2S.

(iii) pH of liquid R is 10. Hence, substance R is a base.

(iv) Salt S is prepared by reacting dilute sulphuric acid with copper oxide. Hence, salt S is copper sulphate. 

Solution 2014-2

(i) Sodium carbonate crystals on reaction with dilute HCl form sodium chloride, water and carbon dioxide, which is evolved with brisk effervescence. This is a neutralisation reaction as sodium carbonate is a basic salt, while hydrochloric acid is an acid. The chemical equation for this reaction is as follows:

 Na2CO3 + 2HCl 2NaCl +H2O + CO2

(ii) Calcium nitrate solution on reaction with excess of sodium hydroxide produces calcium hydroxide and sodium nitrate. Calcium nitrate reacts with excess of sodium hydroxide to form a white precipitate of calcium hydroxide, which is sparingly soluble, and colourless sodium nitrate. The reaction is as follows:

 Ca(NO3)2 + 2NaOH Ca(OH)2 + 2NaNO3

(iii) Acidified aqueous copper sulphate solution is electrolysed with copper electrodes by electrolysis. The electrolysis of an aqueous solution of copper sulphate using copper electrodes (i.e. using active electrodes) results in the transfer of copper metal from the anode to the cathode during electrolysis. Copper sulphate is ionised in aqueous solution.

 Chemical equation:

 CuSO4  Cu2+ + SO42- 

 The positively charged copper ions migrate to the cathode, where each gains two electrons to become copper atoms which are deposited on the cathode.

 Cu2+ + 2e-  Cu  

  Hence, the colour of copper sulphate changes from blue to colourless.

(iv) When ammonium chloride is heated with calcium hydroxide, ammonia gas is released.  

 2NH4Cl + Ca(OH)2 CaCl2 + 2NH3 + 2H2O

 The liberated gas turns red litmus blue.

(v) When moist starch iodide paper is introduced into chlorine gas, chlorine oxidises iodide to iodine, which shows up as blue when it forms a complex with starch. 

Solution 2015

(i) Zn2+

(ii) Cu2+

(iii) Ca2+

(iv) NH4+ 

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 12 - Practical Work Page/Excercise 313

Solution 2015-2

(i) Chloride ion (Cl-)

(ii) Carbonate (CO32-)

(iii) Sulphate (SO42-) 

Solution 2015-3

(i) A deliquescent salt: MgCl2

(ii) An insoluble chloride: AgCl

(iii) On heating, this salt gives a yellow residue when hot and a white residue when cold: ZnCO3

(iv) On heating this salt, a brown-coloured gas is evolved: Ca(NO3)2 

Solution 2015-4

(i) 

(ii) 

(iii) 

Solution 2016-1

(i) Fe3+ ion

  

(ii) Pb2+ ion

(iii)  Ca2+ ion

    

Solution 2016-2

(i) Sulphur dioxide

 Freshly prepared K2Cr2O7 paper changes from orange to green.

(ii) Hydrogen sulphide

 The gas released has a rotten egg smell.

Solution 2017-1

(i) KCl

(ii) ZnCO3

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter 12 - Practical Work here. Our Frank Textbook Solutions for ICSE Class 10  Chemistry are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

Text Book Solutions

ICSE X - Chemistry

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