Class 9 SELINA Solutions Maths Chapter 27 - Graphical Solution (Solution of Simultaneous Linear Equations, Graphically)
Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) Exercise Ex. 27(A)
Solution 1
(i)
The graph x= 5 in the following figure is a straight line AB which is parallel to y axis at a distance of 5 units from it.
(ii)
x+5=0 Þx = -5
The graph x= -5 in the following figure is a straight line AB which is parallel to y axis at a distance of 5 units from it in the negative x direction.
(iii)
The graph y = 7 in the following figure is a straight line AB which is parallel to x axis at a distance of 7 units from it.
(iv)
y+7=0 
y = -7
The graph y = -7 in the following figure is a straight line AB which is parallel to x axis at a distance of 7 units from it in the negative y direction.
(v)
2x + 3y = 0
3y=-2x
(vi)
3x + 2y = 6
2y=6-3x
(vii)
x-5y+4=0
5y=4+x
(viii)
5x + y + 5 = 0
y = -5x - 5
Solution 2
From the figure it is clear that, the graph meets the coordinate
axes at (3, 0) and (0, 5)
From the figure it is clear that, the graph meets the coordinate
axes at (-9, 0) and (0, 6)
Solution 3
The straight line cuts the co-ordinate axis at A(0, 12) and B(-9, 0).
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
(i)
(ii)
Graphical Solution (Solution of Simultaneous Linear Equations, Graphically) Exercise Ex. 27(B)
Solution 1
(i)
(ii)
(iii)
(iv)
Solution 2
Solution 3
Solution 4
Solution 5
(i)
(ii)
(iii)
Solution 6
(ii)
Solution 7
Solution 8
(i)
(ii)
Solution 9
(i)
No. of articles to be manufactured and sold are 50 when there is no loss and no profit.
C.P = S.P = Rs.200
(ii)
(a)
On article 30,
C.P = Rs.140 and S.P. = 120
Therefore Loss = 140 - 120 = Rs.20
(b)
On article 60,
C.P.=Rs.230 and S.P.= Rs.240
Therefore Profit = 240 - 230 = Rs.10
Solution 10
Solution 11
Solution 12
Therefore the solution of the given system of equations is (2,1).
Solution 13
Solution 14
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