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# Class 11-science NCERT Solutions Maths Chapter 6 - Linear Inequalities

## Linear Inequalities Exercise Ex. 6.1

### Solution 1 ### Solution 2 ### Solution 3 ### Solution 4 ### Solution 5 ### Solution 6 ### Solution 7 ### Solution 8 ### Solution 9 ### Solution 10 ### Solution 11 ### Solution 12 ### Solution 13 ### Solution 14 ### Solution 15 ### Solution 16 ### Solution 17 ### Solution 18 ### Solution 19 ### Solution 20 ### Solution 21 ### Solution 22 ### Solution 23 ### Solution 24 ### Solution 25 ### Solution 26 ## Linear Inequalities Exercise Ex. 6.2

### Solution 1 ### Solution 2 ### Solution 3 ### Solution 4 ### Solution 5 ### Solution 6 ### Solution 7 ### Solution 8 ### Solution 9 ### Solution 10 ## Linear Inequalities Exercise Ex. 6.3

### Solution 1 ### Solution 2 ### Solution 3 ### Solution 4

x + y ≥ 4   … (1)

2x – y < 0  … (2)

The graph of the lines, x + y = 4 and 2x – y = 0 are drawn in the figure below.

Inequality (1) represents the region above the line x + y = 4. (including the line x + y = 4)

It is observed that (–1, 0) satisfies the inequality, 2x – y < 0.

[2(-1) – 0 = -2< 0]

Therefore, inequality (2) represents the half plane corresponding to the line, 2x – y = 0 containing the point (-1, 0). [excluding the line 2x – y < 0]

Hence, the solution of the given system of linear inequalities is represented by the common shaded region including the points on the line x + y = 4 and excluding the points on line 2x – y = 0 as follows: ### Solution 5 ### Solution 6 ### Solution 7 ### Solution 8 ### Solution 9 ### Solution 10 ### Solution 11 ### Solution 12 ### Solution 13 ### Solution 14  ### Solution 15  ## Linear Inequalities Exercise Misc. Ex.

### Solution 1 ### Solution 2 ### Solution 3 ### Solution 4 ### Solution 5 ### Solution 6 ### Solution 7 ### Solution 8 ### Solution 9 ### Solution 10 ### Solution 11 ### Solution 12 ### Solution 13  ### Solution 14 