NCERT Solutions for Class 11-science Maths Chapter 11 - Conic Sections

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Chapter 11 - Conic Sections Ex. 11.1

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Chapter 11 - Conic Sections Ex. 11.2

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Chapter 11 - Conic Sections Ex. 11.3

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Chapter 11 - Conic Sections Ex. 11.4

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Vertices (0, ± 3), foci (0, ± 5)

Here, the vertices are on the y-axis.

begin mathsize 12px style therefore the space equation space of space the space hyperbola space is space of space the space form space straight y squared over straight a squared minus straight x squared over straight b squared equals 1. end style

Since the Vertices are (0, ± 3), a = 3

Since the foci are (0, ± 5), c = 5

We know that a2 + b2 = c2

∴ 32 + b2 = 52

∴ b2 = 25 - 9 = 16

begin mathsize 12px style therefore the space equation space of space the space hyperbola space is space of space the space form space straight y squared over 9 minus straight x squared over 16 equals 1. end style

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Chapter 11 - Conic Sections Misc. Ex.

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