ICSE Class 10: Similar Triangles Videos | Properties of Similar triangles
Properties of Similar triangles
The video explains a question based on properties of similar triangles i.e. their corresponding sides are in proportion
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- in triangle abc, AB=8 cm, AC= 10 cm and angle B is 90 degree. P and Q are points on the sides AB and AC respectively such that PQ = 2 cm and angle PQA is 90 degree. Find area of apq
- A metal beam, AB is 6 metres long. It is hinged at the top , P, of a vertical post 1 metre high. When B touched the ground as shown in figure 1. When A comes down to the ground , B rises , as shown in the figure 2. By calculating the length of AP, or otherwise , find the height of B above the ground.
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Altitudes BN and CM of triangle ABC meet at age prove that
CN.HM=BM.HN
HC/HB =√[(CN.HN)/BM.HM]
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In the given figure,PQ || RS || TU,PQ=5cm,TU=7.5cm,RU=a and RS=b
T.P:UTR ~PQR and then solve for a and b
- What is the length of an altitude of an equilateral triangle with side a.
- Prove that the ratio of perimeter of two similar triangles is proportional to the ratios of corresponding sides of the triangles
- In triangle ABC, angle ABC is equal to twice the angle ACB, and bisector of angle ABC meets the opposite side at point P. Show that: ¡) CB:BA=CP:PA ii) AB*BC=BP*CA
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Prove.
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Plz solve the sum