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Class 11-science H C VERMA Solutions Physics Chapter 4 - The Forces

The Forces Exercise 62

Solution 1

(b) Electromagnetic

Solution 2

(d) E > G > N 

Solution 3

(d) irrespective of the signs of the charges

Solution 4

(c) 60 N

Solution 5

Neutron exerts gravitational force and nuclear force on proton because neutron is uncharged particle. (a),(c)

Solution 6

Proton exerts gravitational, electromagnetic and nuclear force on a proton because proton is a charges particle (a), (b), (c)

Solution 7

Electromagnetic force is greater than gravitational force and nuclear force.

Also, gravitational force is greater than nuclear force.

(a), (b), (c)

Solution 8

If all matter were made of electrically neutral particles, then there would be no friction, no tension in the string and also it would not be possible to sit on a chair. But earth could move around the sun as it is due to gravitational force.

(a), (b), (c)

Solution 9

Classical physics is used generally for heavenly bodies and do not work for smaller size particle.

Thus motion od cricket ball, motion of dust particles is adequately described by classical physics.

(a), (b)

Solution 10

Maximum magnitude in tension is when the right end is displaced towards right and the left end towards left.

Maximum magnitude in compression is when the right end is displaced towards left and the left end towards right.

(a), (d)

Solution 11

According to the third law of motion, every action has equal and opposite reaction. Thus, action and reaction act on different objects, have equal magnitude, have opposite direction and have resultant zero.

(a), (b), (c), (d)

The Forces Exercise 63

Solution 1

  

6.67 × 10-17 =   

r2 =   

r = 1 m.

Solution 2

Force acting on us = mg

Let m = 60 kg

Then, F = W = m × g = 60 × 10

F = 600 N.

Solution 3

F = W

  

  

  

If m = 49 kg

r = 4285.7 m

Solution 4

Gravitational force   

  ---(1)

Coulomb's Force   

  

Now,

F1 = F2

  

  

  

Solution 5

  and   

  

  

  

Solution 6

Net Force

F = kx

150 = k × 0.2

k = 750 N/m

Solution 7

  

  

  

h2 + 2Rh-R2 = 0

Solving equation,

  

  

  

  

  

 2649.6   2650 km

Solution 8

  

  

  

  

  

  

Solution 9

  

  

  

  

Solution 10

63×R SAQ - 10 Find the ratio.

  

  

  

  

Ratio is

  

  

Solution 11

(a)   

  

(b)   

  

Solution 12

  

  

  

  

  

  

W = M  = 120 × 0.223 

W = 27 N 

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