Class 11-science H C VERMA Solutions Physics Chapter 21 - Speed of Light
448
Speed of Light Exercise 448
Solution 1
D = 12 km = 12 × 103 m
n = 180
c = 3 × 108 m/s
Using,
C = (2Dnw) ÷ п
W = [п × (3 x 108) ] ÷ [2 (12 × 103) (180)] rad/sec
W = [(п × 105 )÷(8 × 180)] × [180 ÷ п] deg/sec
W = 1.25 × 104 deg/sec
Solution 2
R = 16 m ; b = 6 m ; a = 2 m ; s = 0.7 cm = 0.7 × 10-3 m
W = 256 rev/sec
W = 256 × 2п rad/sec
Speed of Light
C = (4R2wa) ÷ S(R+b)
= [4 × (16)2 × 256 × 2п × 2] ÷ [0.7 × 10-(16+6)]
C = 2.975 × 108 m/s
Solution 3
D = 4.8 km
D = 4.8 x 103 m ; N = 8
Using
C = (DWN) ÷ (2п)
W = (2пC) ÷ (DN) rad/sec
W= C ÷ (DN) rev/sec
= [3 × 108] ÷ [(4.8 × 103) × (8)]
W = 7.8 × 103 rev/sec
