FRANK Solutions for Class 9 Physics Chapter 6 - Light - Reflection of Light
Understand syllabus concepts easily with the support of Frank Solutions for ICSE Class 9 Physics Chapter 6 Light - Reflection of Light. Go through the points that distinguish divergent beam of light and convergent beam of light. Relearn the concept of rectilinear propagation of light. Also, revise the laws of reflection by utilising TopperLearning’s well-written textbook solutions.
Some of the other topics that you can revise through ICSE Class 9 Frank Solutions include lateral inversion, plane mirror, etc. In addition, learn to draw the correct diagram to show reflected and incident rays as per the given information in a Physics question.
Chapter 6 - Light - Reflection of Light Exercise 245
(a). Natural, for e.g. Sun
(b). Artificial, for e.g. Light bulb.
(a). Light waves can travel through vacuum
(b). Light waves are transverse waves
(c). Wavelength of light waves is short so that their length is measured in centi-microns.
(d). The velocity of light in vacuum is 3 x 108 m/s.
(a). Light waves can travel through vacuum while sound waves cannot.
(b). Light waves are transverse waves while sound waves are longitudinal waves.
(c). The velocity of light in air is 3 x 108 m/s while the speed of light in air is just about 330 m/s.
Chapter 6 - Light - Reflection of Light Exercise 246
(b). Divergent beam of light
(c). Divergent beam of light
(d). Parallel beam of light
(a). Sunlight coming through a hole in a dark room, we can easily see that light travels in a straight line
(b). Light coming from a laser light, used for presentation, can also be seen to travel in straight line.
(a). The incident ray, the reflected ray, and the normal at the point of incidence, all lie in the same plane.
(b). The angle of incidence and the angle of reflection are always equal.
(a). Angle of incidence = angle of mirror to the normal - angle between incident ray and mirror
= 90 - 35 = 55o
(b). Angle of reflection = angle of incidence = 55o
(c). Total angle turned = angle of incidence + angle of reflection
= 55 + 55 = 110o
(d). The angle between incident ray and reflected ray = Angle of incidence + Angle of reflection = 55 + 55 = 110o
(a). Distance of image from mirror = distance of boy from the mirror = 3 m
Distance between boy and his image = distance of boy from the mirror + distance of image from mirror = 3+3 = 6 m
(b). Now, distance of boy from the mirror = 4 m
Distance of image from mirror = 4 m
Distance between boy and his image = distance of boy from the mirror + distance of image from mirror = 4+4 = 8 m.
Chapter 6 - Light - Reflection of Light Exercise 247
(a). Image is erect and virtual
(b). Image and object are of same size.
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