FRANK Solutions for Class 9 Physics Chapter 5 - Heat - Thermometry
Manage your last-minute revision of syllabus concepts easily with Frank Solutions for ICSE Class 9 Physics Chapter 5 Heat – Thermometry. Understand the principle used in the making of a thermometer. Also, find out why mercury is used in a thermometric liquid and not water.
You need a thorough understanding of concepts to score top marks in your ICSE Class 9 Physics exam. For conceptual clarity, TopperLearning helps you with reliable textbook solutions, video lessons and self-assessment resources. To resolve doubts related to Thermometry, ask questions through our ‘UnDoubt’ platform.
Chapter 5 - Heat - Thermometry Exercise 209
(i) The substance should have high coefficient of expansion so that it is sensitive to the smallest change in temperature
(ii) The substance should have uniform expansion all over its entire volume
(iii) The substance should have minimum specific heat so that it absorbs minimum heat from the body under measurement.
(i) It does not have uniform expansion.
(ii) Mercury is less sensitive than alcohol as its coefficient of expansion is less than alcohol.
(i) Mercury is good conductors of heat.
(ii) Mercury have high coefficient of expansion thus is sensitive to the smallest change in temperature.
(iii) Freezing points is very low and boiling point is high.
To K = 0oC + 273
To K =273 K.
We know C/100 = (F - 32)/180.
C =5/9(F- 32)
C = 5/9(98.4 - 32)
C = 5/9 X66.4
C =36.88oC
Temperature of body of healthy man is 36.88oC.
Conversion of temperature from Celsius to Kelvin scale is
Temperature in Kelvin To K = Temperature in Celsius To C + 273.
So a rise of temperature of 1oC in Celsius scale is equal to rise of 1oK in Kelvin scale.
C =5/9(F- 32)
9/5C + 32 =F
F = 9/5C + 32.
Temperature given in Celsius = -15oC.
F = 9/5 X (-15) +32
F = -27 +32
F = 5oF.
Temperature in Kelvin To K = Temperature in Celsius To C + 273.
0oK = To C +273.
To C = -273oC.
Absolute zero of temperature on Celsius scale is -273oC.
We know C/100 = (F - 32)/180.
C =5/9(F- 32)
9/5C + 32 =F
F = 9/5C + 32.
So, difference of 1o in Celsius scale is equal to the difference of 9/5o in Fahrenheit scale.
Thus, Difference of 1oC of temperature of two bodies in Celsius scale is equal to difference of 1.8o in Fahrenheit scale.
Chapter 5 - Heat - Thermometry Exercise 210
1 J is amount of heat required to raise the temperature of a body by 1/4.12oC of temperature.
C/100 = (F - 32)/180.
Temperature of steam point on Fahrenheit scale =212o
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