# Class 10 FRANK Solutions Physics Chapter 1.4 - Work, Energy, Power and Their Relation with Force

Access Frank Solutions for ICSE Class 10 Physics Chapter 1.4 Work, Energy, Power and their Relation with Force** **at TopperLearning. Revise chapter terms such as work, power, watt, joule and more through our Physics solutions. Find out whether work done is a vector quantity or a scalar quantity. Through the chapter solutions, our experts also guide you in solving simple calculations on work done using the relevant formula.

In addition, practise important ICSE Class 10 Physics MCQs from this chapter through our online practice tests. You could also revise important Physics chapter concepts with our study materials like concept videos, question papers, Selina Solutions etc.

## Work, Energy, Power and Their Relation with Force Exercise 37

### Solution 1

Force

### Solution 2

Yes

### Solution 3

Joule

### Solution 4

Work

### Solution 5

1N, 1m in its own direction

### Solution 6

When no net force is applied, the work done which is the dot product of force and displacement is zero.

## Work, Energy, Power and Their Relation with Force Exercise 38

### Solution 7

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### Solution 15

It is equal to the product of force and the displacement of the point of application of the force in the direction of force.

### Solution 16

(i) the magnitude and direction of the applied force, and

(ii) the displacement it produces.

### Solution 17

### Solution 18

^{o}.

### Solution 19

### Solution 20

When the angle between the direction of motion and that of the force is 90°;

W = Fd cos 90° = 0

When the angle between the direction of motion and that of the force is 0°;

W = Fd cos 0° = Fd

Hence in the second case, when the angle is 0°; the work done is more.

### Solution 21

The displacement of the man and suitcase is along the horizontal direction. Thus, the angle between the displacement and the force of gravity is 90°;

Thus, W = Fd cos 90° = 0

Hence, no work is done against gravity in this case.

### Solution 22

### Solution 23

W = Fd cos 90

^{0}= 0

### Solution 24

1 kJ = 10

^{3}joules

### Solution 25

^{6}joules

### Solution 26

1 joule of work is said to be done when a force of 1 newton displaces a body through 1 metre in its own direction.

### Solution 27

1 joule = 10

^{7}erg

Thus the ratio is 10

^{7}: 1

### Solution 28

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### Solution 30

Applied force, displacement in the direction of the applied force.

### Solution 31

(i) In free fall of a body of mass m, under gravity from a height h, the force of gravity (F=mg) is in the direction of displacement (=h) and the work done by the gravity is mgh.

(ii) A coolie lifting a load does work against gravity.

### Solution 32

(i) the magnitude and direction of the applied force, and

(ii) the displacement it produces.

### Solution 33

### Solution 34

Or, W = mgh

### Solution 35

^{0};

Thus, W = Fd cos 90

^{0}= 0

Hence, no work is done against gravity in this case; however some work is done against friction.

### Solution 36

### Solution 37

### Solution 38

The SI unit of work is 'joules' and that of power is 'watt'.

### Solution 39

(a) joule, watt

(b) power, energy

(c) work

(d) 10^{7}

(e) 746

### Solution 40

## Work, Energy, Power and Their Relation with Force Exercise 39

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### Solution 42

Power