# Class 10 FRANK Solutions Physics Chapter 5.2 - Change of State and Latent Heat

Understand concepts easily with the support of Frank Solutions for ICSE Class 10 Physics Chapter 5.2 Change of State and Latent Heat. Revise the principle of calorimetry. In addition, grasp the application of heat-related concepts to understand real-life scenarios such as the usage of cooling agents in automobile radiators.

Relearn concepts such as latent heat, specific heat, regelation, heat capacity etc. by practising TopperLearning’s ICSE Class 10 Physics textbook solutions. Still have doubts? Visit our ‘UnDoubt’ section to get them resolved by Physics experts.

## Change of State and Latent Heat Exercise 241

### Solution 1

^{o}C.

It is not same as heat capacity.

### Solution 2

^{-1}K

^{-1}.

### Solution 3

### Solution 4

When a hot body is mixed or kept in contact with a cold body, there is a transfer of heat from hot body to cold body such that

Total heat gained by colder body = Total heat lost by the hot body,

if there is no loss of heat to the surroundings.

### Solution 5

^{o}C.

### Solution 6

The product of mass and specific heat is known as heat capacity.

### Solution 7

### Solution 8

### Solution 9

The amount of heat required to raise the temperature of a body by 1^{o}C is called Heat capacity.

### Solution 10

^{o}C.

### Solution 11

^{-1}K

^{-1}.

### Solution 12

The substances like water which have high heat capacity warm up more slowly than substances like iron which have low heat capacity.

### Solution 13

### Solution 14

### Solution 15

^{o}C absorbs 336 J of heat energy to convert into water at 0

^{o}C.

### Solution 16

When a liquid is solidified, it may either expand or contract. As water freezes to form ice it expands and increases in volume by 10 per cent.

### Solution 17

### Solution 18

### Solution 19

### Solution 20

### Solution 21

### Solution 22

^{o}C into water at the same temperature.

### Solution 23

^{o}C to steam at the same temperature.

### Solution 24

The physical quantity which does not change during change of state is temperature of the body.

### Solution 25

^{o}C absorbs 336000 J of heat energy to convert into water at 0

^{o}C. Therefore,1 kg of water at 0

^{o}C has 336000 J heat energy more than 1 kg ice at 0

^{o}C. So, ice appears colder than water.

### Solution 26

^{o}C because every gram of steam gives out 2260 J of heat energy while condensing. This much quantity of heat is additional to the heat contained in 1 g of boiling water.

### Solution 27

The unit of heat capacity in CGS system is calorie/^{o}C.

### Solution 28

1 cal g^{-1} ^{o}C^{-1} = 239 J kg^{-1} ^{o}C^{-1}

### Solution 29

^{-1}

^{o}C

^{-1}of heat is required to raise the temperature of 1g of the body by 1

^{o}C.

### Solution 30

C = 0.04 cal g

^{-1}

^{o}C

^{-1}

Heat capacity = m x C = 4 cal

^{o}C

^{-1}

### Solution 31

### Solution 32

### Solution 33

^{-1}K

^{-1}.

### Solution 34

### Solution 35

### Solution 36

### Solution 37

## Change of State and Latent Heat Exercise 242

### Solution 38

### Solution 39

### Solution 40

### Solution 41

Temperature remains constant when ice melts at 0^{o}C.

### Solution 42

### Solution 43

### Solution 44

### Solution 45

Mass of ice, m=2g

Amount of heat required convert 2g of ice at 0

^{o}C into water at 0

^{o}C = m x L

= 2 x 336 = 672 J

### Solution 46

Latent heat of vapourisation of water, L=540 cal/g

Mass of water, m=100g

Amount of heat required convert 100g of water at 100^{o}C into steam at 100^{o}C = m x L

= 100 x 540 = 5.4 kJ

### Solution 47

### Solution 48

^{o}C because ice appears colder than water at 0

^{o}C.

### Solution 49

### Solution 50

### Solution 51

^{o}C (because the part BC represents condensation where the vapour changes into liquid without the change in temperature.

(b)DE represents freezing of the substance where the liquid changes into solid at a constant temperature of 100

^{o}C.

(c)Melting point is the temperature of the region DE where liquid changes into solid i.e., 100

^{o}C.

## Change of State and Latent Heat Exercise 243

### Solution 52

### Solution 53

^{o}C.

ii.CD represents the change of state from liquid to vapour i.e., CD represents boiling of water at 100

^{o}C.

iii.The ice initially is in solid state at -10

^{o}C. On heating, its temperature rises to 0

^{o}C. It then takes some heat at 0

^{o}C to melt in water at 0

^{o}C which is its latent heat.