FRANK Solutions for Class 10 Maths Chapter 7 - Problems Based On Quadratic Equations
Get the support ofFrank Solutions for ICSE Class 10 Mathematics Chapter 7 Problems Based on Quadratic Equations to practise Maths problems. Learn the usage of various problem-solving methods such as the formula method, factorisation method etc. to solve quadratic equations.
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Chapter 7 - Problems Based On Quadratic Equations Exercise Ex. 7.1
The sum of the square of the 2 consecutive natural numbers is 481. Find the numbers.
A two digit number is such that its product of its digit is 18. When 63 is subtracted from the number, the digits interchange their places. Find the number.
A two digit number is such that the product of the digits is 14. When 45 is added to the number, then the digit are reversed. Find the number.
Divide 25 into two parts such that twice the square of the larger part exceeds thrice the square of the smaller part by 29.
The sum of the square of 2 positive integers is 208. If the square of larger number is 18 times the smaller number, find the numbers.
The difference of the square of two natural numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
A two digit number is four times the sum and 3 times the product of its digits, find the number.
Two natural numbers differ by 4. If the sum of their square is 656, find the numbers.
The sum of the square of 2 consecutive odd positive integers is 290.Find them.
Three consecutive natural numbers are such that the square of the first increased by the product of other two gives 154. Find the numbers.
The sum of the square of two numbers is 233. If one of the numbers is 3 less than twice the other number. Find the numbers.
Find two natural numbers which differ by 3 and whose squares have the sum of 117.
A two digit number is such that the product of its digit is 8. When 18 is subtracted from the number, the digits interchange its place. Find the numbers.
A two digit number is such that the product of the digit is 12. When 36 is added to the number, the digits interchange their places. Find the numbers.
A two digit number is 4 times the sum of its digit and twice the product of its digit. Find the number.
Three years ago, a man was 5 times the age of his son. Four years hence, he will be thrice his son's age. Find the present ages of the man and his son.
The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.
The present age of the mother is square of her daughter's present age. 4 years hence, she will be 4 times as old as her daughter. Find their present ages.
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
The hypotenuse of a right-angled triangle is 17cm. If the smaller side is multiplied by 5 and the larger side is doubled, the new hypotenuse will be 50 cm. Find the length of each side of the triangle.
The hypotenuse of a grassy land in the shape of a right triangle is 1 m more than twice the shortest side. If the third side is 7m more than the shortest side, find the sides of the grassy land.
The length of the sides forming a right angle in a triangle are 5x cm and (3x-1) cm. If the area of the triangle is 60cm2, find the hypotenuse.
The area of right-angled triangle is 600cm2. If the base of the triangle exceeds the altitude by 10cm, find the dimensions of the triangle.