FRANK Solutions for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry

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Chapter 5 - Mole Concept And Stoichiometry Exercise 115

Question 14

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Solution 14

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 1

State:
(a) Gay-Lussac's law of combining volumes
(b) Avogadro's law

Solution 1

(a) Gay-Lussac's law: It states that 'when gases react, they do so in volumes which bear a simple ratio to one another, and also to the volume of the gaseous product, provided all the volumes are measured at the same temperature and pressure'.
(b) Avogadro's law : It states that 'Under the same conditions of temperature and pressure, equal volumes of all gases contain the same number of molecules'.

Question 2
(a) Define atomicity of a gas.
(b) Differentiate between 2H and H2.
Solution 2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 3
When stating the volume of a gas, the pressure and temperature should also be given. Why?
Solution 3
When stating the volume of a gas, the pressure and temperature should also be given because the volume of a gas is highly susceptible to slight change in pressure and temperature of the gas.
Question 4
(a) The relative atomic mass of Cl atom is 35.5 a.m.u. Explain this statement.
(b) What is the value of Avogadro's number?
(c) What is the value of molar volume of a gas at STP?
Solution 4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 5
Define the terms:
(a) Vapour density.
(b) Molar volume.
(c) Relative atomic mass.
(d) Avogadro's number.
(e) Relative molecular mass.
Solution 5
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 6
(a) What are the main applications of Avogadro's law?
(b) How does Avogadro's law explain Gay - lussac's law of combining volumes?
Solution 6
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 7

Explain the terms:
(a) Gram atom
(b) Gram mole

(c) Mole

Solution 7

(a) Gram atom: "The quantity of the element which weighs equal to its gram atomic mass is called one gram atom of that element".
For example: The gram atomic mass of hydrogen is 1g. So, 1g of hydrogen is 1 gram atom of hydrogen.
(b) Gram mole: "A sample of substance with its mass equal to its gram molecular mass is called one gram molecule of this substance or one gram mole".
For example: Gram molecular mass of oxygen is 32 g. So One gram mole of oxygen is 32g.

Question 8
Calculate the relative molecular masses of (use K = 39, Cl = 35.5, O = 16, C = 12, H = 1, Na = 23, N = 14, S= 32)
(a) Potassium chlorate
(b) Sodium acetate
(c) Chloroform
(d) Ammonium sulphate
Solution 8
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 9
Explain the terms empirical formula and molecular formula.
Solution 9
Empirical formula:"Empirical formula of a compound is the formula which gives the number of atoms of different elements present in one molecule of the compound, in the simplest numerical ratio".
Molecular formula: "Molecular formula of a compound denotes the actual number of atoms of different elements present in one molecule of the compound".
Question 10
Give the empirical formula of:
(a) C6H6
(b) C6H12O6
(c) C2H2
(d) CH3COOH
Solution 10
(a) The empirical formula of C6H6 is: CH
(b) The empirical formula of C6H12O6 is: CH2O.
(c) The empirical formula of C2H2 is: CH
(d) The empirical formula of CH3COOH is: CH2O.
Question 11

Give three pieces of information conveyed by the formula H2O.

Solution 11

Three pieces of information conveyed by the formula H2O is that:

It shows that there are 2hydrogen atoms and 1oxygen atoms present in H2O.
The hydrogen and oxygen atoms are present in simplest whole number ratio of 2:1.
It represents one molecule of compound water.

Question 12
What do you understand by the term mole? How many elementary units are in one mole of a substance?
Solution 12
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 13
Fill in the blanks:
(a) Molecular weight of a gas is twice its ______.
(b) Mass of 22.4 litre of a gas at STP is ______.
(c) One gram atom of an element contains ______ atoms.
(d) One a.m.u. is the mass of ______ atom of C12.
(e) Avogadro's number is equal to ______.
Solution 13
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 15
Give examples of compounds whose:
(a) Empirical formula is the same as the molecular formula.
(b) Empirical formula is different from the molecular formula.
Solution 15
(a) Na2SO4.10H2O.
(b) C6H12O6.

Chapter 5 - Mole Concept And Stoichiometry Exercise 116

Question 16
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 16
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 17
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 17
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 18
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 18
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 19
Calculate the percentage composition of oxygen in lead nitrate [Pb(NO3)2]. [Pb = 207, N= 14, O = 16]
Solution 19
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 20

The usefulness of a fertilizer depends upon percentage of nitrogen present in it. Find which of the following is a better fertilizer:
(a) Ammonium nitrate [NH4NO3]
(b) Ammonium phosphate [(NH4)3PO4] (N=14,H=1,O=16,P=31)

Solution 20

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 21
A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]
Solution 21
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 22
Empirical formula of a compound is CH2O. If its empirical formula is equal to its vapour density, calculate the molecular formula of the compound.
Solution 22
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 23
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 23
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 24
(a)What is the volume occupied by the following gases at STP?
(i) 48 g of oxygen.
(ii) 16 g of sulphur dioxide.
(b) Determine the  molecular mass of a gas if 5g of it occupy a volume of 4 L at STP.
Solution 24
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 25
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 25
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 26
Calculate the percentage of water in ferrous sulphate crystals [Fe = 56, S = 32, O =16, H = 1].
Solution 26
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 27
An organic compound has the following percentage composition: C = 12.76%, H = 2.13%, Br = 85.11%. The vapour density of the compound is 94. Find out its molecular formula.
Solution 27
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 28
Two oxides of a metal (M) have 20.12% and 11.19% oxygen. The formula of the first oxide is MO. Determine the formula of the second oxide.
Solution 28
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 29
Calculate the volume of air at STP, required to convert 300 mL of sulphur dioxide to sulphur trioxide. Air contains 21% of oxygen by volume.
Solution 29
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 30
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 30
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 31
A student puts his signature with graphite pencil. If the mass of carbon in the signature is 10-12 g. Calculate the number of carbon atoms in the signature.
Solution 31
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 117

Question 1996-1
Under the same conditions of temperature and pressure you collect 2 L of carbon dioxide, 3L of chlorine, 5 L of hydrogen, 4 L of nitrogen and 1 L of sulphur dioxide. In which gas sample will there be :
(a) The greatest number of molecules.
(b) The least number of molecules.
Justify your answer.
Solution 1996-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1996-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 1996-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1996-3
Find the total percentage of oxygen in magnesium nitrate crystal Mg(NO3)2.6H2O.
[H = 1, N = 14, O = 16, Mg = 24]
Solution 1996-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1996-4
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Solution 1996-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1997-1
(a) Is it possible to change the temperature and pressure of a fixed mass of a gas without changing its volume? Explain your answer.
(b) Define or explain the meaning of term 'molar volume'.
Solution 1997-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1997-2
What is the mass of nitrogen in 1000 Kg of urea [CO(NH2)2] ?
[H = 1, C= 12, N= 14, O = 16]
Solution 1997-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1997-3

(a) Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)
(b) The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.

Solution 1997-3

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 1997-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 1997-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1998-1

(a) Calculate the percentage of boron (B) in borax (Na2B4O7.10H2O). [H = 1, B = 11, O = 16, Na = 23] , answer correct to 1 decimal place).
(b) (i) The compound A has the following percentage composition by mass:
C =26.7%, O = 71.1%, H = 2.2%. Determine the empirical formula of A.(Answer to one decimal place) (H=1,C=12,O=16)
(ii) If the relative molecular mass of A is 90, what is the molecular formula of A?

Solution 1998-1

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 118

Question 1998-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 1998-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1999-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 1999-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1999-2
If a crop of wheat removes 20 Kg of nitrogen per hectare of soil, what mass of the fertilizer calcium nitrate, Ca(NO3)2 would be required to replace nitrogen in 10 hectare field? (N = 14, O = 16, Ca = 40)
Solution 1999-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 1999-3
(a) A vessel contains N molecules of oxygen at a certain temperature and pressure. How many molecules of sulphur dioxide can the vessel accommodate at the same temperature and pressure?
(b) Each of the two flasks contains 2.0 g of gas at the same temperature and pressure. One flask contains oxygen and the other hydrogen.
(i) Which sample contains the greater number of molecules?
(ii) If the hydrogen sample contains N molecules, how many molecules are present in oxygen sample?
Solution 1999-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2000-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2000-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2000-2

Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]

Solution 2000-2

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 119

Question 2001-1
When gases react their volumes bear a simple ratio to each other, under the same conditions of temperature and pressure. Who proposed this gas law?
Solution 2001-1
Gay - Lussac proposed this law.
Question 2001-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2001-2
Molecular mass of ethane = 30
According to Gay-Lussac's law:
2 vol. of C2H6 requires= 7 vol. of oxygen
Vol. of C2H6 = 2 vol. = 100 L
Vol. of oxygen required = 7 vol. =350 L
Question 2001-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2001-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2001-4
Mention the term defined by the following sentence:
The mass of a given volume of gas compared to the mass of an equal volume of hydrogen.
Solution 2001-4
The term is vapour density.
Question 2001-5
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2001-5
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2001-6

Calculate the percentage of phosphorous in the fertilizer superphosphate, Ca(H2PO4)2. [Ca = 40, H =1, P =31, O = 16] (Correct to 1 decimal place)

Solution 2001-6

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2001-7
A metal M, forms a volatile chloride containing 65.5% Chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride. [M = 56, Cl = 35.5]
Solution 2001-7
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2002-1

Samples of the gases O2, N2, CO2 and CO under the same conditions of temperature and pressure contain the same number of molecules represented by X. The molecules of Oxygen, occupy V litres and have a mass of 8 g. Under the same conditions of temperature and pressure:
(a) What is the volume occupied by:
(i) X molecules of N2,
(ii) 3X molecules of CO? [C=12,N=14,O=16]
(b)  What is the mass of CO2 in g?
(c) In answering the above questions, which law have you used?

Solution 2002-1

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2002-2

Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2PtCl6. [N = 14, H = 1, Pt = 195, Cl =35.5] (Give your answer correct to the nearest whole number)

Solution 2002-2

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2002-3
The percentage composition of sodium phosphate, as determined by analysis is: 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound. [H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]
Solution 2002-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 120

Question 2003-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2003-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2004-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2004-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2004-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2004-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2005-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2005-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 121

Question 2006-1
(a) The volumes of gases A, B, C and D are in the ratio, 1:2:2:4 under the same conditions of temperature and pressure.
(i) Which sample of gas contains the maximum number of molecules?
(ii) If the temperature and the pressure of gas A are kept constant then what will happen to the volume of A when the number of molecules is doubled?
(iii) If this ratio of gas volumes refers to the reactants and products of a reaction, which gas law is being observed?
(iv) If the volume of A is actually 5.6 dm3 at STP, calculate the number of molecules in the actual volume of D at STP.
(v) Using your answer from (iv), state, the mass of D if the gas is dinitrogen oxide (N2O)
(b) Calculate the percentage of nitrogen in aluminium nitride. [Al = 27, N = 14]
Solution 2006-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2006-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2006-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2006-3

(a) Calculate the number of moles and number of molecules present in 1.4 g of ethylene gas. What is the volume occupied by the same amount of ethylene?
(b) What is the vapour density of ethylene? (Avogadro's number = 6x1023; Atomic weight of C = 12, H = 1; Molar volume = 22.4 litres at STP)

Solution 2006-3

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2006-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2006-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2007-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2007-1
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 122

Question 2007-2
A compound 'X' consists of 4.8% of C and 95.2% of Br by mass.
(i) Determine the empirical formula of this compound. [C = 12, Br = 80]
(ii) If the vapour density of the compound is 252, what is the molecular formula of the compound?
(iii) Name the type of chemical reaction by which X can be prepared from ethane.
Solution 2007-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2008-1
Choose the correct alternative:
The gas laws which relates the volume of a gas to the number of molecules of the gas is:
(a) Avogadro's  law
(b) Gay-Lussac's law
(c) Boyle's law
(d) Charle's law
Solution 2008-1
The gas laws which relates the volume of a gas to the number of molecules of the gas is avogadro's law
Question 2008-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2008-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2008-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2008-3
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 123

Question 2009-1
Choose the correct answer:
A gas cylinder of capacity of 20 dm3 is filled with gas X the mass of which is 10 g. When the same cylinder is filled with hydrogen gas at the same temperature and pressure the mass of the hydrogen is 2 g, hence the relative molecular mass of the gas is:
(a) 5
(b) 10
(c) 15
(d) 20
Solution 2009-1
The relative molecular mass of the gas is 10.
Question 2009-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2009-2
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2009-3
Correct the following statement:
Equal masses of all gases under identical conditions contain the same number of molecules.
Solution 2009-3
The correct statement is that equal volumes of all gases under identical conditions contain the same number of molecules.
Question 2009-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Solution 2009-4
Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry
Question 2010-1

(i) LPG stands for liquefied petroleum gas. Varieties of LPG are marketed including a mixture of propane (60%) and butane (40%). If 10 litre of this mixture is burnt, find the total volume of carbon dioxide gas added to the atmosphere. Combustion reaction can be presented as :

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(ii) Calculate the percentage of nitrogen and oxygen in ammonium nitrate [Relative molecular mass of ammonium nitrate is 80, H=1, N=14, O = 16].

 

Solution 2010-1

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(ii) Molecular mass of NH4(NO3) = 80

H = 1, N = 14, O = 16

% of nitrogen

As 80 g of NH4 (NO3) contains 28 g of nitrogen,

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry 

% of nitrogen

As80 g of NH4(NO3) contains48 g of oxygen

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry 

Question 2010-2

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

(i) Write the equation for the reaction.

(ii) What is the mass of 4.5 moles of calcium carbonate? Relative molecular mass of calcium carbonate is 100)

(iii) What is the volume of carbon dioxide liberated at STP?

(iv) What mass of calcium chloride is formed? (Relative molecular mass of calcium chloride is 111)

(v) How many moles of HCl are used in this reaction

 

Solution 2010-2

(i) Equation for the reaction of calcium carbonate with dilute hydrochloric acid:

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(ii) Relative molecular mass of calcium carbonate=100

 Mass of 4.5 moles of calcium carbonate

 = No. of moles× Relative molecular mass

 = 4.5×100

 = 450g

(iii) Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry 

 As100g of calcium carbonate gives 22.4dm3 of CO2,

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

(iv) Molecular mass of calcium carbonate =100

 Relative molecular mass of calcium chloride =111

 As 100 g of calcium carbonate gives 111g of calcium chloride,

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(v) Molecular mass of HCl=36.5

 Molecular mass of calcium carbonate =100

 As 100 g of calcium carbonate gives (2×36.5)= 73g of HCl,

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 124

Question 2011-1

(i) Calculate the volume of 320 g of SO2 at STP (Atomic mass : S = 32 and O = 16)

(ii) State Gay-Lussac's Law of combining volumes.

(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 of propane (C3H5). (Atomic mass : C = 14, O = 16, H = 1, Molar Volume = 22.4 dm3 at STP)

Solution 2011-1

(i) Atomic mass: S = 32 and O = 16

 Molecular mass of SO2=32+(2×16)=64g

 As 64 g of SO2 = 22.4dm3,

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

(ii) Gay-Lussac's law: When gases react, they do so in volumes which bear a simple ratio to one another and to the volume of the gaseous product, if all the volumes are measured at the same temperature and pressure.

 

(iii) C3H8 + 5O2  3CO2 + 4H2O

 Molar mass of propane = 44

 44 g of propane requires 5 × 22.4 litres of oxygen at STP.

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2011-2

An organic compound with vapour density = 94 contains C = 12.67%, H = 2.13% and Br = 85.11%. Find the molecule formula.

[Atomic mass C = 12, H = 1, Br = 80]

Solution 2011-2

Element

Relative atomic mass

% Compound

Atomic ratio

Simplest ratio

H

1

2.13

2.13/1 = 2.13

2

C

12

12.67

12.67/12 = 1.055

2

Br

80

85.11

85.11/80 = 1

1

 

Empirical formula = CH2Br

n(Empirical formula mass of CH2Br) = Molecular mass (2 × VD)

n(12 + 2 + 80) = 94 × 2

n = 2

Molecular formula = Empirical formula × 2

= (CH2Br) × 2

= C2H4Br2

Question 2011-3

Calculate the mass of

(i) 1022 atoms of sulphur

(ii) 0.1 mole of carbon dioxide

 [Atomic mass : S = 32,C=12, and O = 16 and Avogadro's number = 6 × 1023]

Solution 2011-3

(i) 1022 atoms of sulphur

 6.022 × 1023 atoms of sulphur will have mass = 32 g

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

(ii) 0.1 mole of carbon dioxide

 1 mole of carbon dioxide will have mass = 44 g

 0.1 mole of carbon dioxide will have mass = 4.4 g

Question 2013-1

O2is evolved by heating KCIO3 using MnO2 as a catalyst.

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

(i) Calculate the mass of KClO3 required to produce 6.72 litre of O2at STP

[Atomic masses : K = 39, Cl = 35.5, O = 16]

(ii) Calculate the number of moles of oxygen present in the above volume and also the number of molecules

(iii) Calculate the volume occupied by 0.01 mole of CO2at STP

Solution 2013-1

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2013-2

Solve the following :

(i) What volume of oxygen is required to burn completely 90dm3 of butane under similar conditions of temperature and pressure?Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry 

(ii) The vapour density of a gas is 8. What would be the volume occupied by 24.0 of the gas at STP?

(iii) A vessel contains X number of molecules of hydrogen gas at a certain temperature and pressure. How many molecules of nitrogen gas would be present in the same vessel under the same conditions of temperature and pressure?

Solution 2013-2

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2014-1

(i) Oxygen oxidase ethyne to carbon dioxide and water as shown by the equation :

2C2H2 + 5O2 4CO2 + 2H2O

What volume of ethylene gas at STP is required to produce 8.4 dm3of carbon dioxide at STP?

 

(ii) A compound made up of two elements X and Y has an empirical formula X2Y. if the atomic weight of X is 10 and that Y is 5 and the compound has a vapour density 25, find its molecular formula.

Solution 2014-1

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 125

Question 2014-2

Give one word or phrase for the following:

(i) The ratio of the mass of a certain volume of gas to the mass of an equal volume of hydrogen under the same conditions of temperature and pressure.

(ii) Formation of ions from molecules

Solution 2014-2

(i) Vapour density

(ii) Ionisation 

Question 2014-3

(i) State Avogadro's Law

(ii) A cylinder contains 68g of ammonia gas at STP

(1) What is the volume occupied by this gas?

(2) How many moles of ammonia are present in the cylinder?

(3) How many molecules of ammonia are present in the cylinder? [N-14,H-1]

Solution 2014-3

 

(i) Avogadro's law:Equal volumes of all gases under similar conditions of temperature and pressure contain the same number of molecules.

(ii)  

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2015-1

Which of the following would weigh the least?

(A) 2 gram atoms of Nitrogen

(B) 1 mole of Silver

(C) 22.4 litres of oxygen gas at 1 atmospheric pressure and 273K

(D) 6.02 × 1023 atoms of carbon

[Atomic masses : Ag = 108, N - 14, O = 16,C = 12]

Solution 2015-1

6.02 × 1023 atoms of carbon

Question 2015-2

Complete the following calculations. Show working for complete credit:

(i) Calculate the mass of calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur. [Atomic masses : S = 32, Ca = 40]

(ii) If 6 litres of hydrogen and 4 litres of chlorine are mixed and exploded and if water is added to the gases formed, find the volume of the residual gas.

(iii) If the empirical formula of a compound is CH and it has a vapour density of 13, find the molecular formula of the compound.

Solution 2015-2

(i) 3.2 g of S has number of atoms = 6.023 × 1023 x 3.2 /32

 = 0.6023 × 1023

 So, 0.6023 × 1023 atoms of Ca has mass=40 × 0.6023 ×1023/6.023 × 1023 = 4g

 

(ii) 6 litres of hydrogen and 4 litres of chlorine when mixed result in the formation of 8 litres of HCl gas.

 When water is added to it, it results in the formation of hydrochloric acid. Chlorine acts as a limiting agent leaving behind only 2 litres of hydrogen gas.

 Therefore, the volume of the residual gas will be 2 litres.

 

(iii)  

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2015-3

Consider the following reaction and based on the reaction answer the questions that follow :

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Calculate :

(i) The quantity in moles of (NH4)2Cr2O7 if 63 gm of (NH4)2Cr2O7 is heated.

(ii) The quantity in moles of nitrogen formed.

(iii) The volume in litres or dm3 of N2evolved at STP

(iv) The mass in grams of Cr2O3 formed at the same time

 [Atomic masses : H = 1, Cr=52, N=14]

Solution 2015-3

(i)  

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(ii) 252 g of ammonium dichromate gives 22.4 dm3of N2

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(iii) 

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(iv) 252 g of ammonium dichromate gives 152 g of CrO3

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2016-1

A gas cylinder contain 12 × 1024 molecules of oxygen gas

If Avogadro's number is 6 × 1023, calculate :

(i) The mass of oxygen present in the cylinder

(ii) The volume of oxygen at STP present in the Cylinder [O = 16]

Solution 2016-1

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2016-2

A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapour density is 29, find its molecular formula.

[C = 12, H = 1]

Solution 2016-2

% of carbon = 82.76%

% of hydrogen = 100 - 82.76 = 17.24%

Element

% Weight

Atomic

Weight

Relative

No. of

moles

Simplest

Ratio

C

82.76

12

82.76/12 =

6.89

6.89/6.8

= 1 × 2 = 2

H

17.24

1

17.24/1 =

17.24

17.24/6.89

= 2.5 × 2 = 5

Empirical formula = C2H5

Empirical formula weight = 2 × 12 + 1 × 5 = 24 + 5 = 29

Vapour density = 29

Relative molecular mass = 29 × 2 = 58

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Chapter 5 - Mole Concept And Stoichiometry Exercise 126

Question 2016-3

The equation 4NH35O2 4NO + 6H2O represents the catalytic oxidation of ammonia. If 100 cm3of ammonia is used, calculate the volume of oxygen required to oxidise the ammonia completely.

Solution 2016-3

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2016-4

A gas of 32 g mass has a volume of 20 litres at STP. Calculate the gram molecular weight of the gas.

Solution 2016-4

Mass of gas = 32 g

Volume occupied by 32g of gas = 20litres

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2016-5

How much calcium oxide is formed when 82 g of calcium nitrate is heated? Also find the volume of nitrogen dioxide evolved:

2Ca(NO3)2 2CaO + 4NO2 + O2 (Ca = 40,N = 14, O = 16)

Solution 2016-5

2Ca(NO3)2 2CaO + 4NO2 + O2

Molecular weight of 2Ca(NO3)2 = 2[40+2(14+48) = 32g

Molecular weight of CaO = 2(40 + 16) = 112g

328 g of Ca(No3]2 liberates 4 moles of NO2

328 g of Ca (NO3)2 liberates 4 × 22.4 L of NO2

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2016-6

The ratio between the number of molecules in 2g of hydrogen and 32 g of oxygen is

(A) 1:2

(B) 1:0:01

(C) 1:1

(D) 0.01:1

[Given that H=1,O=16]

Solution 2016-6

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Question 2017-1

(a) Calculate the number of gram atoms in 4.6 grams of sodium (Na = 23)

(b) Calculate the percentage of water of crystallization in CuSO4. 5H2O

(H = 1, O = 16, S = 32, Cu = 64)

(c) A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.

Solution 2017-1

(a) Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

(b) Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

(c) Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And StoichiometryFrank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry 

Question 2017-2

(a) Propane burns in air according to the following equation :

C3H8 + 5O2 3CO2 + 4H2O

What volume of propane is consumed on using 1000 cm3of air, considering only 20% of air contains oxygen?

 

(b) The mass of 11.2 litres of a certain gas at s.t.p is 24 g. Find gram molecular mass of the gas

Solution 2017-2

(a)  

 Given:

C3H8 + 5O2 3CO2 + 4H2O

Volume of air = 1000 cm3

Percentage of oxygen in air = 20%

From the given information,

 Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

According to Gay-Lussac's law,

1 vol. of propane consumes 5 vol. of oxygen.

Volume of oxygen = 1000 cm3 × 20% = 200 cm3

 

Therefore,

Volume of propane burnt for every 200 cm3 of oxygen,

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

40 cm3of propane is burnt. 

 

(b)  

(i) Given:

 Volume of gas at STP = 11.2 litres

Mass of gas at STP = 24 g

Gram molecular mass = ?

Mass of 22.4 L of a gas at STP is equal to its gram

molecular mass.

 

11.2 L of the gas at STP weighs 24 g

So,

22.4 L of the gas will weigh

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

Gram molecular mass = 48 g 

Question 2017-3

A gas cylinder can hold 1 kg of hydrogen at room temperature and pressure.

(a) Find the number of moles of hydrogen present

(b) What weight of CO2can the cylinder hold under similar conditions of temperature and pressure? (H = 1 C = 12, O = 16)

(c) If the number of molecules of hydrogen in the cylinder is X, calculate the number of CO2 molecules in the cylinder with the same conditions of temperature and pressure.

(d) State the law that helped you to arrive at the above result

Solution 2017-3

(a)  

 Given:

Mass of hydrogen = 1 kg at 298 K and 1 atm pressure

 Moles of hydrogen =?

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry 

(b) Molecular mass of CO2 = 12 + 2 × 16 = 44g

So, vapour density (VD) = mol. Mass/2 = 44/2 = 22

Frank Solutions Icse Class 10 Chemistry Chapter - Mole Concept And Stoichiometry

 

(c) According to Avogadro's law, equal volumes of all gases under similar conditions of temperature and pressure contain equal number of molecules.

 

(d) So, number of molecules of carbon dioxide in the cylinder = number of molecules of hydrogen in the cylinder = X