FRANK Solutions for Class 10 Biology Chapter 5 - Transpiration
Find the complete Frank Solutions for ICSE Class 10 Biology Chapter 5 Transpiration at TopperLearning. Understand what is transpiration, what happens during transpiration and when does it occur in plants with our detailed solutions for Biology revision. Learn to write about the opening and closing mechanism of stomata with supporting diagrams by practising with our Frank Solutions.
Understand the importance of transpiration in plants by going through our chapter-specific ICSE Class 10 Biology textbook solutions. In addition, explore our practice tests and Biology mock question papers for improved board exam preparation.
Chapter 5 - Transpiration Exercise 60
(i) What is transpiration?
(ii) In which form, water comes out in transpiration?
(iii) Where does transpiration take place in leaves? Give names of the various parts.
(iv) Give one important difference between transpiration and evaporation.
(v) When does stomatal transpiration take place in plants?
(vi) From which structure cuticular transpiration occur in plants?
(vii) How does transpiration take place in night?
(viii) What is the effect of temperature on transpiration?
(ix) What is the impact of more atmospheric pressure on transpiration?
(x) What is the relationship between transpiration water and water absorbed from the soil?
(ii) During transpiration, water comes out in the form of water vapour.
(iii) Transpiration takes place in leaves through stomata. Stomata consist of guard cells, epidermal cells, chloroplast and nucleus.
(iv) The important difference between transpiration and evaporation is that transpiration is the loss of water from the aerial parts of the plant while evaporation is loss of water from any surface.
(v) Stomatal transpiration occurs mainly during the day time when the guard cells of stoma are fully turgid and the stomata are fully open.
(vi) Cuticular transpiration occurs through the cuticle which is present on the epidermis of leaves & herbaceous stem.
(vii) Rate of transpiration slows down at night because photosynthesis does not take place and the stomata remains closed.
(viii) There is a direct effect of temperature on transpiration as the increase in temperature results in increase in the rate of transpiration.
(ix) When the atmospheric pressure is higher, less water vapour is lost and the rate of transpiration lowers.
(x) The relationship between transpiration water and water absorbed from the soil is that if the soil is deficient in water then the rate of water absorption decreases which hence decreases the rate of transpiration and if the soil has excessive water then the rate of water absorption increases which in turn increases the rate of transpiration.
(a) Cuticular transpiration (b) Lenticular transpiration (c) Stomatal transpiration
(a) Respiration (b) Guttation (c) Bleeding
Chapter 5 - Transpiration Exercise 61
Following are its importance in plants:
1. It causes transpirational pull which helps in the absorption of water.
2. It produces a cooling effect.
3. It helps in the ascent of sap.
Stomata are minute pores of elliptical shape surrounded by two specialized epidermal cells called guard cells.These guard cells are kidney shaped which control the opening and closing of stomata.It also consists of nucleus, stoma, epidermis and chloroplast.
1. It causes transpirational pull which helps in the absorption of water.
2. It produces a cooling effect.
3. It helps in the ascent of sap.
(i) Hydathodes
(ii) Guttation
(i) a windy day (ii) a foggy day?
(ii) A foggy day: On a foggy day the area outside the leaf is saturated with water. So, water vapour from the leaves is removed very slowly thereby reducing transpiration.
(i) Name the apparatus.
(ii) What is it used for?
(iii) What is the role played by the air bubble in this experiment?
(iv) Of what use is the reservoir?
(ii) Potometer is used to measure the rate of transpiration.
(iii) The rate of movement of the air bubble will indicate the rate of transpiration.
(iv) The reservoir is used to provide water to the potometer.
(i) in dark.
(ii) in sunlight.
(iii) in front of a fan?
Give a reason in each case.
Reason: During dark, stomata remains closed due to which the rate of transpiration decreases which hence decreases the movement of air bubble.
(ii) Movement of the air bubble will be faster.
Reason: During sunlight, stomata remains opened due to which the rate of transpiration increases which hence increases the movement of air bubble.
(iii) Movement of the air bubble will be faster.
Reason: Moving air produces dry air which increases the rate of transpiration which hence increases the movement of air bubble.
A well-watered potted plant shows wilting of leaves on a hot sunny day.
(i) Transpiration and evaporation
(ii) Guttation and bleeding
(iii) Cuticular transpiration and lenticular transpiration
(iv) Stomata and lenticels
1. High intensity of light 2. High temperature 3. Low humidity
Chapter - Exercise
Chapter 5 - Transpiration Exercise 62
The three uses of this phenomenon are:
(i) It helps in transportation of water and minerals to the various parts of the plant.
(ii) It produces a cooling effect to the plants.
(iii) It evaporates excess water.
(ii) Write the correct substitutes for only the first two words if it is a wrong statement.
(ii) Cobalt chloride (CoCl2) paper
Loss of water as droplets through leaves of an intact plant is termed ______. (Bleeding/ Guttation/ Transpiration)
1. Sunken stomata
2. Modification of leaves into spines
3. Presence of thick cuticle
(i) What is the aim of the experiment?
(ii) Why has oil been put in each test tube?
(iii) What will be the observations in the two test-tubes after about 2-3 days?
(iv) Give reasons to explain any change observed as answered in (iii) above.
(v) Why has the test-tube b without the plant, been taken in the experiment?
(ii) To prevent the evaporation of water from the surface.
(iii) The level of water in test tube (a) will decrease.
(iv) The fall in the water level in the test tube (a) is because of transpiration through aerial parts of the plant.
(v) Test tube (b) has been taken as a control experiment. Since no transpiration takes place without the plant.
(i) If the rate of transpiration becomes more than the rate of photosynthesis, plant will
(a) Continue to live, but will not be able to store food.
(b) Be killed instantly.
(c) Grow more vigorously because more energy will be available.
(d) Stop growing and gradually die of starvation.
(ii) Transpiration pull will be maximum under which of the following conditions?
(a) Open stomata, dry atmosphere and moist soil.
(b) Open stomata, high humid atmosphere and well irrigated soil.
(c) Open stomata, high humid atmosphere and dry soil.
(d) Closed stomata, dry atmosphere and dry soil.
(ii) (a) open stomata, dry atmosphere and moist soil.
Hydathodes: ______
(i) Why was the plant initially kept in darkness for 24 hours?
(ii) What is the function of sodium hydroxide solution in the flask?
(iii) Select the correct leaf from the five available choices shown in the diagram as a, b, c, d and e. Rewrite the correct answer by filling in the appropriate letter for the questions that follow:
1. After the starch test, leaf x would look like ______.
2. After the starch test, leaf y would look like ______.
(iv) The experiment with leaf y shows that photosynthesis requires the presence of certain factors. Mention any one factor.
(ii) Sodium hydroxide absorbs CO2 thereby making the flask CO2 free.
(iii) (1) C, (2) E
(iv) Sunlight
Chapter 5 - Transpiration Exercise 63
(i) What is the purpose of keeping CaCl2 vials inside the cup?
(ii) After a few hours, CaCl2 vials were taken out and weighed again.
will you except any difference in weight? If so, give reasons.
(iii) What was expect the purpose of using a manometer?
(iv) What do you mean by transpiration?
(ii) Yes, the weight of CaCl2 vials kept on the lower side will be more because transpiration will be more on the lower surface and the moisture absorbed.
(iii) To check the outside and inside pressure.
(iv) Transpiration is the loss of water from the aerial parts of the plant in the form of water vapour.
(i) Name the parts labeled A and B.
(ii) What is the biological term for the above structure?
(iii) What is the function of the part labeled A?
(iv) Mention two structural features of A, which help in the function mentioned in (iii) above?
(v) Where is this structure likely to be found in a leaf?
(vi) The structure (fig.5.22) helps in the process of transpiration. Explain the term transpiration.
(vii) How many other cells are found surrounding this structure as seen in the diagram?
B = Stomatal aperture
(ii) Stomata
(iii) The function of the guard cells are that they help to regulate the rate of transpiration by opening and closing the stomata thus preventing excessive water loss.
(iv) The two structural features of guard cells are :
1.The guard cells have thin outer wall and thick inner wall.
2. Guard cells contain chloroplast in their cytoplasm.
(v) These are present on the lower surface of the dorsiventral leaf.
(vi) Transpiration is the loss of water in the form of water vapour from aerial parts of the plant.
(vii) Five
Chapter 5 - Transpiration Exercise 64
(i) Which one is responsible for guttation?
(a) Diffusion (b) Root pressure (c) Transpiration (d) Photosynthesis
(ii) Rate of transpiration is more, when
(a) High humidity is present in atmosphere.
(b) Air may be stopped.
(c) Extra water is in sky.
(d) Environmental conditions may dry.
(iii) Stomata open during day time because guard cells
(a) Do photosynthesis and synthesis osmotically active.
(b) Are of thin walls.
(c) Are of bean shape.
(d) Help in exchange of gases.
(iv) The cause of wilting is more
(a) respiration (b) photosynthesis (c) absorption (d) transpiration
(v) Guttation is a mechanism of removal of water from plant by
(a) Stomata (b) hydathodes (c) lenticles (d) wounds
(vi) Secretion of sap from apex of non-injured leaf is called
(a) Evaporation (b) guttation (c) evapo-transpiration (d) transpiration
(vii) Transpiration is more
(a) From the upper surface of leaf.
(b) From the lower surface of leaf.
(c) From stem.
(d) From upper and lower surface of leaf.
(viii) The rate of transpiration is determined with the following instrument
(a) Potometer (b) Evaporimeter (c) Atmometer (d) Perimeter
(ix) In herbaceous plants, following percentage of absorbed water comes out
(a) 80 (b) 60 (c) 90 (d) 40
(x) Transpiration rate is high, when
(a) Atmospheric water is saturated with vapour.
(b) Light is very dim.
(c) Temperature is low.
(d) Atmosphere is dry and temperature is high.
(xi) More water loss in plants is the cause of wilting. This can be checked by
(a) Keeping plant in bright light
(b) Spraying alcohol on the plant
(c) Layering the bottom with Vaseline
(d) Giving more fertilizer to the soil
(xii) The percentage of cuticular transpiration in plants is
(a) Approximately 10%
(b) Approximately 20%
(c) Approximately 25%
(d) Approximately 30%
(xiii) Transpiration generates
(a) Suction force
(b) capillary force
(c) Imbibitions force
(d) atmospheric pressure
(xiv) Transpiration rate is low
(a) due to less surface area of leaf
(b) benting of leaf
(c) By sunken stomata
(d) all of these
(xv) Stomata can open in night also in
(a) xerophyte
(b) gametophyte
(c) hydrophyte
(d) none of these
(xvi) Who had said that "transpiration is a necessary evil"?
(a) Curtis (b) Steward (c) Anderson (d) J.C. Bose
(ii) (d) environmental conditions may dry
(iii) (a) do photosynthesis and synthesis osmotically active
(iv) (d) Transpiration
(v) (d) hydathodes
(vi) (b) guttation
(vii) (b) From the lower surface of leaf
(viii) (a) Potometer
(ix) (c) 90
(x) (d) atmosphere is dry and temperature is high
(xi) (c) layering the bottom with vaseline
(xii) (a) approximately 10%
(xiii) (a) suction force
(xiv) (d) all of the above
(xv) (a) xerophyte
(xvi) (a) Curtis
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