A question was put up in the lesson on Standing Waves Part 2 (Physics 11th Class) . The question and the choice of answers is reproduced below :
"A stretched string of length 1 m is fixed at both ends. The lowest frequency at which t
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Lowest frequency corresponds to highest wavelenngth.
Image the string plucked in the middle, and what you observe is just 1/2 the complete wave.
λ/2 = L
λ = 2L = 2 m
speed = wavelength x frequency
= 2 x 440 = 880 m/s