Question
Sat March 07, 2015

# Prove that the circle drawn with any side of a rhombus as a diameter, passes through the point intersection of its diagonals.

Mili Hariyani
Sat March 07, 2015

Let PQRS be a rhombus with diagonals PR and QS which intersect at O.

We know that diagonals of rhombus intersect each other at right angles. Therefore

Here we have circles passing through PQ, QR, RS, SP as diametre and they pass through O.

For the circle with PQ as diameter, we have angle POQ inscribed in the semi-circle. Also angle inscribed in a semi-circle is a right angle.

Thus, the circle passes through O.

This is true for any circle constructed on any of the side of rhombus.

Therefore, circle with the side of rhombus as diameter passes through the point of intersection of its diagonals.

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# In circle ,ABC is an isosceles triangle with AB=AC and P is point on side AC.Through C a line is drawn to intersect BP produced in Q,such that angle ABQ=angle ACQ.   PROVE THAT :ANGLE AQC=90 DEGREE+1/2 OF ANGLE A.

Thu March 10, 2016