Question
Fri September 28, 2012 By:

# not able open the ans.

Fri September 28, 2012

4 cosec2 A + 9 sin2 A = 4/ sin2 A + 9 sin2 A = (4 + 9 sin4 A)/ sin2 A

Let F(A) = (4 + 9 sin4 A)/ sin2 A

FÂ’(A) = [(4 Ã— 9 sin3 A. cos A) (sin2 A) - (4 + 9 sin4 A) Ã— 2 cos A. sin A] / (sin2 A)2

This on further simplification gives

FÂ’(A) =  2cos A. (9 sin4 A - 4)/ sin3 A

To find the maximum or the minimum value, it is required to consider, 2cos A. (9 sin4 A - 4)/ sin3 A = 0

This gives cos A = 0 or sin2 A = 2/3.

The maximum value of cosec2 A is infinite. In that case sin2 A = 0.

So, maximum value of F(A) is infinite.

When cos A = 0 i.e. sin2 A = 1, then F(A) = 4 Ã— 1 + 9 Ã— 1 = 13

When sin2 A = 2/3, i.e. cosec2 A = 3/2, then F(A) = 4 Ã— 3/2 + 9 Ã— 2/3 = 12.

Among 12 and 13, the minimum value is 12.

So, the minimum value of F(A) is 12.

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